K\u00fctle: De\u011fi\u015fmeyen madde miktar\u0131d\u0131r.(Hacmi dolduran atom say\u0131s\u0131d\u0131r.) m= gram, kg
\nK\u00fctle e\u015fit kollu terazi ile \u00f6l\u00e7\u00fcl\u00fcr.
\nA\u011f\u0131rl\u0131k: Cismin k\u00fctlesi ile yer \u00e7ekim ivmesinin \u00e7arp\u0131m\u0131na denir.
\nG = m.g g = Yer\u00e7ekimi ivmesi = 9,81 ? 10 metre\/saniye2
\nm = k\u00fctle G =a\u011f\u0131rl\u0131k<\/p>\n
Yer\u00e7ekimi ivmesi(g): K\u00fctlelerin fark\u0131ndan dolay\u0131 cisimlerin veya yerin cisimler \u00fczerine uygulad\u0131\u011f\u0131 kuvvete denir. Yer\u00e7ekimi ivmesi d\u00fcnya y\u00fczeyinde: yer merkezinden uzakla\u015ft\u0131k\u00e7a azal\u0131r, yakla\u015ft\u0131k\u00e7a da bu de\u011fi\u015fim \u00e7ok k\u00fc\u00e7\u00fckt\u00fcr. Kutuplardaki yer\u00e7ekimi ivmesi ekvatordaki yer \u00e7ekim ivmesinden daha b\u00fcy\u00fckt\u00fcr.<\/p>\n
B\u00fcy\u00fck bir cisim d\u00fc\u015f\u00fcnelim. Bir ucu ekvatorda di\u011fer ucu kutuplarda olsun. K\u00fctle merkezi ekvatorla kutup ortas\u0131nda iken A\u011f\u0131rl\u0131k merkezi kutuplara yak\u0131n olur. K\u00fc\u00e7\u00fck cisimler i\u00e7in K.M ile ile A\u011f\u0131rl\u0131k merkezi ayn\u0131 yerde al\u0131nabilinir.
\nK\u00fctle A\u011f\u0131rl\u0131k
\n1-m ile g\u00f6sterilir. 1-G ile g\u00f6sterilir.
\n2-Birimi kg\u2019d\u0131r. 2-Birimi gr\u2019d\u0131r.
\n3-E\u015fit kkollu terazi ile \u00f6l\u00e7\u00fcl\u00fcr. 3-Dinamometre ile \u00f6l\u00e7\u00fcl\u00fcr.
\n4-Yer\u00e7ekimine ba\u011fl\u0131 de\u011fildir.4-Yer\u00e7ekimine ba\u011fl\u0131d\u0131r.
\n5-Yer\u00e7ekimi de\u011fi\u015fmez. 5-Yer\u00e7ekimine ba\u011fl\u0131d\u0131r.<\/p>\n
Not: A\u011f\u0131rl\u0131k dinamometre ile(yayl\u0131 el kantar\u0131) \u00f6l\u00e7\u00fcl\u00fcr.<\/p>\n
Soru: D\u00fcnyadaki k\u00fctlesi 60 kg olan bir adam\u0131n ;<\/p>\n
a) D\u00fcnyadaki k\u00fctlesini( g D\u00fcnya=10m \/ s2 al\u0131n\u0131z. )
\nb) D\u00fcnyadaki a\u011f\u0131rl\u0131\u011f\u0131n\u0131 bulunuz?
\na) m= 60 kg (k\u00fctle de\u011fi\u015fmez)
\nb) G =m.g 60.10 = 600 N<\/p>\n
Soru: m =60 kg yer\u00e7ekimi ivmesi d\u00fcnyan\u0131n g d\u00fcnya \/6 yere g\u00f6t\u00fcr\u00fcl\u00fcrse(Aya); <\/p>\n
a) m= ? 60 kg(de\u011fi\u015fmez)
\nb) G= ? G=m.g = 60 * 10 \/ 6= 100 N<\/p>\n
E\u015e\u0130T KOLLU TERAZ\u0130<\/p>\n
1-Moment prensibi:
\nKuvvet x kuvvet kolu = Y\u00fck x y\u00fck kolu
\nX.AO = Y.BO+M.n
\nAO = N = BO = B\u00f6lme say\u0131s\u0131
\nm:binicinin k\u00fctlesi
\nn: binicinin yeriX = Y+
\nx: \u00f6l\u00e7en k\u00fctle, y: \u00f6l\u00e7\u00fclen k\u00fctle
\nNOT: Terazinin hassasiyeti denir. Yani terazi bundan daha k\u00fc\u00e7\u00fck de\u011ferleri \u00f6l\u00e7emez.<\/p>\n
Soru:<\/p>\n
2 graml\u0131k binici sa\u011f kolda 6. b\u00f6lmede iken x
\ncismi 13 gr\u2019la dengeleniyor. Kol uzunlu\u011fu 10. b\u00f6lme ise x ka\u00e7 gr ? <\/p>\n
x= 13+m.n = 13+2.6 x =13+1,2 =14,2 gr<\/p>\n
Soru:<\/p>\n
AO = 10 b\u00f6lme = N m = 2 gr n = 6
\nY = x+m.n13 =x+2.6 13 \u2013 1,2 = x<\/p>\n
x = 11,8 gr<\/p>\n
Soru: K\u00fctleleri 45 ve 60 k\u011f olan Ali ile Mehmet \u015fekildeki gibi tahterevallide dengelenmek istiyorlar.
\na) Ali\u2019nin yan\u0131na ka\u00e7 kg daha kolmal\u0131d\u0131r?
\n15 + 45 = 60 kg<\/p>\n
b) Ali\u2019nin \u00f6n\u00fcne B\u2019ye ka\u00e7 kg konmal\u0131d\u0131r?
\nSa\u011f = Sol60.2 = 45.2 + x.1
\n120 = 90 + x x = 30 kg<\/p>\n
HATALI TERAZ\u0130:
\nTerazinin sa\u011f kolu sol koluna e\u015fit de\u011filse bu tip terazilere hatal\u0131 terazi denir. K\u00fctlenin ger\u00e7ek de\u011ferini bulmak i\u00e7in k\u00fctle, sa\u011f ve sol kolda ayr\u0131 ayr\u0131 \u00f6l\u00e7\u00fclerek bulunur. <\/p>\n
Ger\u00e7ek k\u00fctle =<\/p>\n
MGer\u00e7ek =
\nSoru: Kollar\u0131n uzunlu\u011fu e\u015fit olmayan bir terazinin sa\u011f kefesinde tart\u0131lan bir cisim 1,8 gr geliyor.Sol kefede tart\u0131l\u0131rsa 5 gr geliyor.Cismin ger\u00e7ek k\u00fctlesi ka\u00e7 gramd\u0131r?<\/p>\n
Sola bSa\u011f Sola bSa\u011f
\n1,8 gr xx5 g<\/p>\n
1,8xa = x.b1,8a=x.xax2= 5.1,8
\n5
\nx.a = 5.b b =x.ax =x =
\n5
\nx = 3 gr<\/p>\n
23\/11\/2006 – \u00d6zk\u00fctle ve A\u011f\u0131rl\u0131k-1
\nYazar: Metin
\nK\u00dcTLE VE A\u011eIRLIK<\/p>\n
K\u00fctle: De\u011fi\u015fmeyen madde miktar\u0131d\u0131r.(Hacmi dolduran atom say\u0131s\u0131d\u0131r.) m= gram, kg
\nK\u00fctle e\u015fit kollu terazi ile \u00f6l\u00e7\u00fcl\u00fcr.
\nA\u011f\u0131rl\u0131k: Cismin k\u00fctlesi ile yer \u00e7ekim ivmesinin \u00e7arp\u0131m\u0131na denir.
\nG = m.g g = Yer\u00e7ekimi ivmesi = 9,81 ? 10 metre\/saniye2
\nm = k\u00fctle G =a\u011f\u0131rl\u0131k<\/p>\n
Yer\u00e7ekimi ivmesi(g): K\u00fctlelerin fark\u0131ndan dolay\u0131 cisimlerin veya yerin cisimler \u00fczerine uygulad\u0131\u011f\u0131 kuvvete denir. Yer\u00e7ekimi ivmesi d\u00fcnya y\u00fczeyinde: yer merkezinden uzakla\u015ft\u0131k\u00e7a azal\u0131r, yakla\u015ft\u0131k\u00e7a da bu de\u011fi\u015fim \u00e7ok k\u00fc\u00e7\u00fckt\u00fcr. Kutuplardaki yer\u00e7ekimi ivmesi ekvatordaki yer \u00e7ekim ivmesinden daha b\u00fcy\u00fckt\u00fcr.<\/p>\n
B\u00fcy\u00fck bir cisim d\u00fc\u015f\u00fcnelim. Bir ucu ekvatorda di\u011fer ucu kutuplarda olsun. K\u00fctle merkezi ekvatorla kutup ortas\u0131nda iken A\u011f\u0131rl\u0131k merkezi kutuplara yak\u0131n olur. K\u00fc\u00e7\u00fck cisimler i\u00e7in K.M ile ile A\u011f\u0131rl\u0131k merkezi ayn\u0131 yerde al\u0131nabilinir.
\nK\u00fctleA\u011f\u0131rl\u0131k
\n1-m ile g\u00f6sterilir. 1-G ile g\u00f6sterilir.
\n2-Birimi kg\u2019d\u0131r. 2-Birimi gr\u2019d\u0131r.
\n3-E\u015fit kkollu terazi ile \u00f6l\u00e7\u00fcl\u00fcr. 3-Dinamometre ile \u00f6l\u00e7\u00fcl\u00fcr.
\n4-Yer\u00e7ekimine ba\u011fl\u0131 de\u011fildir.4-Yer\u00e7ekimine ba\u011fl\u0131d\u0131r.
\n5-Yer\u00e7ekimi de\u011fi\u015fmez. 5-Yer\u00e7ekimine ba\u011fl\u0131d\u0131r.<\/p>\n
Not: A\u011f\u0131rl\u0131k dinamometre ile(yayl\u0131 el kantar\u0131) \u00f6l\u00e7\u00fcl\u00fcr.<\/p>\n
Soru: D\u00fcnyadaki k\u00fctlesi 60 kg olan bir adam\u0131n ;<\/p>\n
a) D\u00fcnyadaki k\u00fctlesini( g D\u00fcnya=10m \/ s2 al\u0131n\u0131z. )
\nb) D\u00fcnyadaki a\u011f\u0131rl\u0131\u011f\u0131n\u0131 bulunuz?
\na) m= 60 kg (k\u00fctle de\u011fi\u015fmez)
\nb) G =m.g 60.10 = 600 N<\/p>\n
Soru: m =60 kg yer\u00e7ekimi ivmesi d\u00fcnyan\u0131n g d\u00fcnya \/6 yere g\u00f6t\u00fcr\u00fcl\u00fcrse(Aya); <\/p>\n
a) m= ? 60 kg(de\u011fi\u015fmez)
\nb) G= ? G=m.g = 60 * 10 \/ 6= 100 N<\/p>\n
E\u015e\u0130T KOLLU TERAZ\u0130<\/p>\n
1-Moment prensibi:
\nKuvvet x kuvvet kolu = Y\u00fck x y\u00fck kolu
\nX.AO = Y.BO+M.n
\nAO = N = BO = B\u00f6lme say\u0131s\u0131
\nm:binicinin k\u00fctlesi
\nn: binicinin yeriX = Y+
\nx: \u00f6l\u00e7en k\u00fctle, y: \u00f6l\u00e7\u00fclen k\u00fctle
\nNOT: Terazinin hassasiyeti denir. Yani terazi bundan daha k\u00fc\u00e7\u00fck de\u011ferleri \u00f6l\u00e7emez.<\/p>\n
Soru:<\/p>\n
2 graml\u0131k binici sa\u011f kolda 6. b\u00f6lmede iken x
\ncismi 13 gr\u2019la dengeleniyor. Kol uzunlu\u011fu 10. b\u00f6lme ise x ka\u00e7 gr ? <\/p>\n
x= 13+m.n = 13+2.6 x =13+1,2 =14,2 gr<\/p>\n
Soru:<\/p>\n
AO = 10 b\u00f6lme = N m = 2 gr n = 6
\nY = x+m.n13 =x+2.6 13 \u2013 1,2 = x<\/p>\n
x = 11,8 gr<\/p>\n
Soru: K\u00fctleleri 45 ve 60 k\u011f olan Ali ile Mehmet \u015fekildeki gibi tahterevallide dengelenmek istiyorlar.
\na) Ali\u2019nin yan\u0131na ka\u00e7 kg daha kolmal\u0131d\u0131r?
\n15 + 45 = 60 kg<\/p>\n
b) Ali\u2019nin \u00f6n\u00fcne B\u2019ye ka\u00e7 kg konmal\u0131d\u0131r?
\nSa\u011f = Sol60.2 = 45.2 + x.1
\n120 = 90 + x x = 30 kg<\/p>\n
HATALI TERAZ\u0130:
\nTerazinin sa\u011f kolu sol koluna e\u015fit de\u011filse bu tip terazilere hatal\u0131 terazi denir. K\u00fctlenin ger\u00e7ek de\u011ferini bulmak i\u00e7in k\u00fctle, sa\u011f ve sol kolda ayr\u0131 ayr\u0131 \u00f6l\u00e7\u00fclerek bulunur. <\/p>\n
Ger\u00e7ek k\u00fctle =<\/p>\n
MGer\u00e7ek =
\nSoru: Kollar\u0131n uzunlu\u011fu e\u015fit olmayan bir terazinin sa\u011f kefesinde tart\u0131lan bir cisim 1,8 gr geliyor.Sol kefede tart\u0131l\u0131rsa 5 gr geliyor.Cismin ger\u00e7ek k\u00fctlesi ka\u00e7 gramd\u0131r?<\/p>\n
Sola bSa\u011f Sola bSa\u011f
\n1,8 gr xx5 g<\/p>\n
1,8xa = x.b1,8a=x.xax2= 5.1,8
\n5
\nx.a = 5.b b =x.ax =x =
\n5
\nx = 3 gr<\/p>\n","protected":false},"excerpt":{"rendered":"
K\u00fctle: De\u011fi\u015fmeyen madde miktar\u0131d\u0131r.(Hacmi dolduran atom say\u0131s\u0131d\u0131r.) m= gram, kg K\u00fctle e\u015fit kollu terazi ile \u00f6l\u00e7\u00fcl\u00fcr. A\u011f\u0131rl\u0131k: Cismin k\u00fctlesi ile yer \u00e7ekim ivmesinin \u00e7arp\u0131m\u0131na denir. G = m.g g = Yer\u00e7ekimi ivmesi = 9,81 ? 10 metre\/saniye2 m = k\u00fctle G =a\u011f\u0131rl\u0131k Yer\u00e7ekimi ivmesi(g): K\u00fctlelerin fark\u0131ndan dolay\u0131 cisimlerin veya yerin cisimler \u00fczerine uygulad\u0131\u011f\u0131 kuvvete denir. …<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1407,1403],"tags":[6768,2106,6769,2110],"class_list":["post-2744","post","type-post","status-publish","format-standard","hentry","category-fen-ve-teknoloji-odevleri","category-odevler","tag-dinamometre","tag-kutle-ve-agirlik","tag-moment-prensibi","tag-yercekimi-ivmesi"],"_links":{"self":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/2744","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/comments?post=2744"}],"version-history":[{"count":0,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/2744\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/media?parent=2744"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/categories?post=2744"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/tags?post=2744"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}