1. Genel Alan Ba\u011f\u0131nt\u0131s\u0131 ABC \u00fc\u00e7geninde [BC] kenar\u0131na ait y\u00fckseklik [AH]<\/p>\n
Bir \u00fc\u00e7genin alan\u0131, bir kenar\u0131 ile o kenara ait y\u00fcksekli\u011fin \u00e7arp\u0131m\u0131n\u0131n yar\u0131s\u0131d\u0131r.<\/p>\n
Hangi kenar\u0131 kullan\u0131rsak kullanal\u0131m \u00fc\u00e7genin alan\u0131 sabittir.Bir ABC \u00fc\u00e7geninde y\u00fckseklik her zaman \u00fc\u00e7genin i\u00e7inde olmayabilir.
\n2. Dik \u00dc\u00e7gende Alan
\nDik \u00fc\u00e7genin alan\u0131 dik kenarlar\u0131n\u0131n \u00e7arp\u0131m\u0131n\u0131n yar\u0131s\u0131na e\u015fittir.
\n3. Bir a\u00e7\u0131s\u0131 ve bu a\u00e7\u0131n\u0131n kenarlar\u0131 bilinen \u00fc\u00e7genin alan\u0131;
\nABC \u00fc\u00e7geninde
\nm(ABC) = a
\n|AB| = c
\n|BC| = a
\na. Birbirini 180\u00b0 ye tamamlayan a\u00e7\u0131lar\u0131n sin\u00fcsleri e\u015fit oldu\u011fundan;<\/p>\n
e\u015fitli\u011fi vard\u0131r.b. |BC| = a |AB| = c uzunluklar\u0131 sabit olan ABC \u00fc\u00e7geninin alan\u0131n\u0131n maksimum olabilmesi i\u00e7in a = 90\u00b0 olmal\u0131d\u0131r.c. Hipoten\u00fcs uzunlu\u011fu sabit olan ABC dik \u00fc\u00e7geninin alan\u0131n\u0131n en b\u00fcy\u00fck de\u011ferini alabilmesi i\u00e7in |AB| = |AC| olmal\u0131d\u0131r. ABC \u00fc\u00e7geni ikizkenar dik \u00fc\u00e7gen olmal\u0131d\u0131r.
\n 4. \u00dc\u00e7 kenar\u0131n\u0131n uzunlu\u011fu verilen \u00fc\u00e7genin alan\u0131; ABC \u00fc\u00e7geninin \u00e7evresi \u00c7evre(ABC) = a + b + c
\n\u00c7evrenin yar\u0131s\u0131na u dersek<\/p>\n
5. \u00c7evresi ve i\u00e7 te\u011fet \u00e7emberinin yar\u0131\u00e7ap\u0131 verilen \u00fc\u00e7genin alan\u0131; ABC \u00fc\u00e7geninin i\u00e7 te\u011fet \u00e7emberinin yar\u0131\u00e7ap\u0131 r olsun.
\nBu \u00fc\u00e7 alan\u0131 toplayarak ABC \u00fc\u00e7geninin alan\u0131n\u0131 bulabiliriz.
\nA(ABC)=u.r
\nBir ABC \u00fc\u00e7geninde i\u00e7 te\u011fet \u00e7emberin yar\u0131\u00e7ap\u0131 r ve y\u00fckseklikler<\/p>\n
ABC dik \u00fc\u00e7geninde A(ABC) = |BD|.|DC|
\n6. Kenarlar\u0131 ve \u00e7evrel \u00e7emberinin yar\u0131\u00e7ap\u0131 verilen ABC \u00fc\u00e7geninin \u00e7evrel \u00e7emberinin merkezi O ve yar\u0131\u00e7ap\u0131 R olsun. <\/p>\n
Orta Dikme
\n\u00dc\u00e7genin kenar\u0131n\u0131n orta noktas\u0131ndan \u00e7izilen dik do\u011frulara orta dikme denir. [EA, a kenar\u0131n\u0131n
\n[FO, b kenar\u0131n\u0131n
\n[DO, c kenar\u0131n\u0131n
\norta dikmeleridir.
\nO noktas\u0131 \u00e7evrel \u00e7emberin merkezidir.
\n7. Y\u00fckseklikleri e\u015fit \u00fc\u00e7genlerin alanlar\u0131 aras\u0131ndaki ba\u011f\u0131nt\u0131;
\nY\u00fckseklikleri e\u015fit \u00fc\u00e7genlerin alanlar\u0131n\u0131n oran\u0131 tabanlar\u0131n\u0131n oran\u0131na e\u015fittir.
\nABC ve ACD \u00fc\u00e7genlerinin tabanlar\u0131 ayn\u0131 do\u011fru \u00fczerinde ve tepe noktalar\u0131 ayn\u0131 noktada oldu\u011funa g\u00f6re, y\u00fckseklikleri e\u015fittir. <\/p>\n
8. Tabanlar\u0131 e\u015fit \u00fc\u00e7genlerin alanlar\u0131n\u0131n oran\u0131 y\u00fcksekliklerinin oran\u0131na e\u015fittir. ABC ve DBC \u00fc\u00e7genlerinin tabanlar\u0131 e\u015fit ve \u00e7ak\u0131\u015f\u0131kt\u0131r.<\/p>\n","protected":false},"excerpt":{"rendered":"
1. Genel Alan Ba\u011f\u0131nt\u0131s\u0131 ABC \u00fc\u00e7geninde [BC] kenar\u0131na ait y\u00fckseklik [AH] Bir \u00fc\u00e7genin alan\u0131, bir kenar\u0131 ile o kenara ait y\u00fcksekli\u011fin \u00e7arp\u0131m\u0131n\u0131n yar\u0131s\u0131d\u0131r. Hangi kenar\u0131 kullan\u0131rsak kullanal\u0131m \u00fc\u00e7genin alan\u0131 sabittir.Bir ABC \u00fc\u00e7geninde y\u00fckseklik her zaman \u00fc\u00e7genin i\u00e7inde olmayabilir. 2. Dik \u00dc\u00e7gende Alan Dik \u00fc\u00e7genin alan\u0131 dik kenarlar\u0131n\u0131n \u00e7arp\u0131m\u0131n\u0131n yar\u0131s\u0131na e\u015fittir. 3. Bir a\u00e7\u0131s\u0131 ve bu …<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1404,1403],"tags":[7230,7229],"class_list":["post-3042","post","type-post","status-publish","format-standard","hentry","category-matematik-odevleri","category-odevler","tag-dik-ucgende-alan","tag-ucgende-alan"],"_links":{"self":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/3042","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/comments?post=3042"}],"version-history":[{"count":0,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/3042\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/media?parent=3042"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/categories?post=3042"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/tags?post=3042"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}