{"id":3088,"date":"2011-10-05T10:03:33","date_gmt":"2011-10-05T07:03:33","guid":{"rendered":"http:\/\/www.islamidavet.com\/kutuphane\/\/?p=3088"},"modified":"2011-10-05T10:03:33","modified_gmt":"2011-10-05T07:03:33","slug":"carpanlara-ayirma","status":"publish","type":"post","link":"https:\/\/www.islamidavet.com\/kutuphane\/carpanlara-ayirma\/","title":{"rendered":"\u00c7arpanlara Ay\u0131rma"},"content":{"rendered":"<p>A. ORTAK \u00c7ARPAN PARANTEZ\u0130NE ALMA <\/p>\n<p> A(x) . B(x) \u00b1 A(x) . C(x) = A(x) . [B(x) \u00b1 C(x)]<br \/>\n En az d\u00f6rt terimi olan ifadeler ortak \u00e7arpan parantezine al\u0131nacak bi\u00e7imde grupland\u0131r\u0131l\u0131r, sonra ortak \u00e7arpan parantezine al\u0131n\u0131r.,<\/p>\n<p> B. \u00d6ZDE\u015eL\u0130KLER<\/p>\n<p> 1. \u0130ki Kare Fark\u0131 &#8211; Toplam\u0131<br \/>\n i. a2\u2013b2=(a\u2013b)(a+b)<br \/>\n ii. a2+b2=(a+b)2\u20132ab ya da<br \/>\n a2+b2=(a\u2013b)2+2ab dir.<br \/>\n 2. \u0130ki K\u00fcp Fark\u0131 &#8211; Toplam\u0131<br \/>\n i. a3\u2013b3=(a\u2013b)(a2+ab+b2)<br \/>\n ii. a3+b3=(a+b)(a2\u2013ab+b2)<br \/>\n iii. a3\u2013b3=(a\u2013b)3+3ab(a\u2013b)<br \/>\n iv. a3+b3=(a+b)3\u20133ab(a+b)<br \/>\n 3. n. Dereceden Fark\u0131 &#8211; Toplam\u0131<br \/>\n i) n bir sayma say\u0131s\u0131 olmak \u00fczere,<br \/>\n xn \u2013 yn = (x \u2013 y) (xn \u2013 1 + xn \u2013 2 y + xn \u2013 3 y2 + &#8230; + xyn \u2013 2 + yn \u2013 1) dir.<br \/>\n ii) n bir tek sayma say\u0131s\u0131 olmak \u00fczere,<br \/>\n xn + yn = (x + y) (xn \u2013 1 \u2013 xn \u2013 2y + xn \u2013 3 y2 \u2013 &#8230; \u2013 xyn \u2013 2 + yn \u2013 1) dir.<br \/>\n 4. Tam Kare \u0130fadeler<br \/>\n i. (a + b)2 = a2 + 2ab + b2<br \/>\n ii. (a \u2013 b)2 = a2 \u2013 2ab + b2<br \/>\n iii. (a + b + c)2 = a2 + b2 + c2 + 2(ab + ac + bc)<br \/>\n iv. (a + b \u2013 c)2 = a2 + b2 + c2 + 2(ab \u2013 ac \u2013 bc)<br \/>\n n bir tam say\u0131 olmak \u00fczere,<br \/>\n (a \u2013 b)2n = (b \u2013 a)2n<br \/>\n (a \u2013 b)2n \u2013 1 = \u2013 (b \u2013 a)2n \u2013 1 dir.,<br \/>\n (a + b)2 = (a \u2013 b)2 + 4ab<br \/>\n 5. (a \u00b1 b)n nin A\u00e7\u0131l\u0131m\u0131<\/p>\n<p> Pascal \u00dc\u00e7geni<\/p>\n<p> (a + b)n a\u00e7\u0131l\u0131m\u0131 yap\u0131l\u0131rken, \u00f6nce a n\u0131n n . kuvvetten ba\u015flayarak azalan, b nin 0 dan ba\u015flayarak artan kuvvetlerinin \u00e7arp\u0131mlar\u0131 yaz\u0131l\u0131p toplan\u0131r.<br \/>\n Sonra n nin Paskal \u00fc\u00e7genindeki kar\u015f\u0131l\u0131\u011f\u0131 bulunarak katsay\u0131lar belirlenir.<br \/>\n (a \u2013 b)n yukar\u0131daki bi\u00e7imde yap\u0131l\u0131r ancak b nin; \u00e7ift kuvvetlerinde terimin \u00f6n\u00fcne (+), tek kuvvetlerinde terimin \u00f6n\u00fcne (\u2013 i\u015fareti konulur.<br \/>\n (a + b)3 = a3 + 3a2b + 3ab2 + b3<br \/>\n (a \u2013 b)3 = a3 \u2013 3a2b + 3ab2 \u2013 b3<br \/>\n (a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 +b4<br \/>\n (a \u2013 b)4 = a4 \u2013 4a3b + 6a2b2 \u2013 4ab3 + b4<br \/>\n C. ax2 + bx + c Bi\u00e7imindeki \u00dc\u00e7 Terimlisinin \u00c7arpanlar\u0131na Ayr\u0131lmas\u0131<br \/>\n 1. a = 1 i\u00e7in,<br \/>\n b = m + n ve c = m . n olmak \u00fczere,<br \/>\n x2 + bx + c = (x + m) (x + n) dir.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A. ORTAK \u00c7ARPAN PARANTEZ\u0130NE ALMA A(x) . B(x) \u00b1 A(x) . C(x) = A(x) . [B(x) \u00b1 C(x)] En az d\u00f6rt terimi olan ifadeler ortak \u00e7arpan parantezine al\u0131nacak bi\u00e7imde grupland\u0131r\u0131l\u0131r, sonra ortak \u00e7arpan parantezine al\u0131n\u0131r., B. \u00d6ZDE\u015eL\u0130KLER 1. \u0130ki Kare Fark\u0131 &#8211; Toplam\u0131 i. a2\u2013b2=(a\u2013b)(a+b) ii. a2+b2=(a+b)2\u20132ab ya da a2+b2=(a\u2013b)2+2ab dir. 2. \u0130ki K\u00fcp Fark\u0131 &hellip;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1404,1403],"tags":[7285,7286,7287,7210],"class_list":["post-3088","post","type-post","status-publish","format-standard","hentry","category-matematik-odevleri","category-odevler","tag-carpanlara-ayirma","tag-iki-kare-farki","tag-iki-kup-farki","tag-pascal-ucgeni"],"_links":{"self":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/3088","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/comments?post=3088"}],"version-history":[{"count":0,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/3088\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/media?parent=3088"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/categories?post=3088"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/tags?post=3088"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}