{"id":3096,"date":"2011-10-05T10:54:05","date_gmt":"2011-10-05T07:54:05","guid":{"rendered":"http:\/\/www.islamidavet.com\/kutuphane\/\/?p=3096"},"modified":"2011-10-05T10:54:05","modified_gmt":"2011-10-05T07:54:05","slug":"obeb","status":"publish","type":"post","link":"https:\/\/www.islamidavet.com\/kutuphane\/obeb\/","title":{"rendered":"Obeb"},"content":{"rendered":"<p>OBEB (ORTAK B\u00d6LENLER\u0130N EN B\u00dcY\u00dc\u011e\u00dc)<br \/>\nOBEB, iki veya daha \u00e7ok say\u0131y\u0131 ayn\u0131 anda b\u00f6lebilen en b\u00fcy\u00fck say\u0131d\u0131r. Verilen say\u0131lar\u0131n OBEB&#8217; ini bulmak i\u00e7in, say\u0131lar asal \u00e7arpanlar\u0131na ayr\u0131l\u0131r ve ortak asal \u00e7arpanlar\u0131n en k\u00fc\u00e7\u00fck \u00fcsleri al\u0131n\u0131r.<br \/>\n1. Aralar\u0131nda asal iki say\u0131n\u0131n OBEB&#8217; i 1&#8242; dir. Yani, a ile b aralar\u0131nda asal iki say\u0131 ise,<br \/>\n(a, b)OBEB = 1 dir.<br \/>\n2. Ayn\u0131 zamanda, ikiden \u00e7ok say\u0131daki say\u0131lardan en az iki tanesi aralar\u0131nda asal ise, bu say\u0131lar\u0131n OBEB&#8217; i 1&#8242; dir. Yani, a, b, c, d, e say\u0131lar\u0131ndan a ile b aralar\u0131nda asal ise,<br \/>\n(a, b, c, d, e)OBEB = 1 dir.<br \/>\n3. \u0130ki veya daha fazla say\u0131n\u0131n ortak tam b\u00f6lenlerinin say\u0131s\u0131, OBEB&#8217; inin b\u00f6lenlerinin say\u0131s\u0131na e\u015fittir.<br \/>\n4. Ard\u0131\u015f\u0131k iki sayma say\u0131s\u0131n\u0131n OBEB&#8217; i 1&#8242; dir. Yani, a ile b ard\u0131\u015f\u0131k iki sayma say\u0131s\u0131 olmak \u00fczere,<br \/>\n(a , b)OKEK = 1 dir.<br \/>\n\u00d6rnek 1:<br \/>\n18, 30, 42 say\u0131lar\u0131n\u0131n OBEB&#8217; i ka\u00e7t\u0131r?<br \/>\n\u00c7\u00f6z\u00fcm:<br \/>\n1. Yol:<\/p>\n<p>18, 30 ve 42 say\u0131lar\u0131n\u0131n \u00fc\u00e7\u00fcn\u00fc birden b\u00f6len say\u0131lar 2 ve 3 t\u00fcr. Dolay\u0131s\u0131yla,<br \/>\n(18, 30, 42)OBEB = 2 . 3 = 6 d\u0131r.<br \/>\n2. Yol:<br \/>\n18 = 2.32<br \/>\n30 = 2.3.5<br \/>\n42 = 2.3.7<br \/>\nHer \u00fc\u00e7 say\u0131n\u0131n ortak asal \u00e7arpanlar\u0131n\u0131n en k\u00fc\u00e7\u00fck \u00fcsl\u00fcs\u00fc al\u0131nmal\u0131d\u0131r. Dolay\u0131s\u0131yla,<br \/>\n(18, 30, 42)OBEB = 2.3 = 6 d\u0131r.<br \/>\n\u00d6rnek 2:<br \/>\n100 ile 120 say\u0131lar\u0131n\u0131n OBEB&#8217; i ka\u00e7t\u0131r?<br \/>\n\u00c7\u00f6z\u00fcm:<br \/>\n1. Yol:<\/p>\n<p>100 ile 120 say\u0131s\u0131n\u0131n ikisini birden b\u00f6len say\u0131lar\u0131 22 ile 5 dir. Dolay\u0131s\u0131yla,<br \/>\n(100, 120)OBEB = 22 . 5 = 4 . 5 = 20 dir.<br \/>\n2. Yol:<br \/>\n100 = 22.52<br \/>\n120 = 23.3.5<br \/>\nHer iki say\u0131n\u0131n ortak asal \u00e7arpanlar\u0131n\u0131n en k\u00fc\u00e7\u00fck \u00fcsl\u00fcs\u00fc al\u0131nmal\u0131d\u0131r. Dolay\u0131s\u0131yla,<br \/>\n(100, 120)OBEB = 22.5 = 20 dir.<br \/>\n\u00d6rnek 3:<br \/>\n6, 15 ve 29 say\u0131lar\u0131n\u0131n OBEB&#8217; i ka\u00e7t\u0131r?<br \/>\n\u00c7\u00f6z\u00fcm:<br \/>\n\u0130kiden \u00e7ok say\u0131daki say\u0131lar\u0131n en az iki tanesi aralar\u0131nda asal ise, bu say\u0131lar\u0131n OBEB&#8217; i 1 oldu\u011fundan, verilen say\u0131lardan 6 ile 29 say\u0131s\u0131 veya 15 ile 29 say\u0131s\u0131 aralar\u0131nda asal oldu\u011fu i\u00e7in<br \/>\n(6, 15, 29)OBEB = 1<br \/>\ndir.<br \/>\n\u00d6rnek 4:<br \/>\n100 ile 120 say\u0131lar\u0131n\u0131n ortak tam b\u00f6lenlerinin say\u0131s\u0131 ka\u00e7t\u0131r?<br \/>\n\u00c7\u00f6z\u00fcm:<br \/>\n(100, 120)OBEB = 22.51 = 20<br \/>\noldu\u011fundan, pozitif b\u00f6lenlerinin say\u0131s\u0131,<br \/>\n( 2 + 1) . ( 1 + 1 ) = 3 . 2 = 6<br \/>\nbulunur. Buradan, t\u00fcm b\u00f6lenlerin say\u0131s\u0131, pozitif b\u00f6lenlerin say\u0131s\u0131n\u0131n iki kat\u0131na e\u015fit oldu\u011fundan,<br \/>\n2 . 6 = 12 olur.<br \/>\n\u00d6rnek 5:<br \/>\nBoyutlar\u0131 9 cm, 12 cm, 15 cm olan dikd\u00f6rtgenler prizmas\u0131 bi\u00e7imindeki kutunun i\u00e7erisi, bo\u015f yer kalmayacak \u015fekilde en b\u00fcy\u00fck boyutlu k\u00fcplerle doldurulmak istenmektedir. Bu kutuya ka\u00e7 tane k\u00fcp yerle\u015ftirilebilir?<br \/>\n\u00c7\u00f6z\u00fcm:<br \/>\nKutu en b\u00fcy\u00fck boyutlu k\u00fcplerle doldurulmak istendi\u011finden, 9 cm, 12 cm, 15 cm say\u0131lar\u0131n\u0131n OBEB&#8217; i bulunmal\u0131d\u0131r. Bu nedenle,<br \/>\n(9, 12, 15)OBEB = 3 t\u00fcr. B\u00f6ylece, en b\u00fcy\u00fck boyutlu k\u00fcp\u00fcn bir kenar\u0131 = 3 cm olur. Bir kenar\u0131 3 cm olacak \u015fekilde yerle\u015ftirilebilecek k\u00fcp say\u0131s\u0131,<br \/>\nK\u00fcp say\u0131s\u0131 = Kutunun hacmi \/ K\u00fcp\u00fcn hacmi = 9.12.15\/3.3.3 = 3.4.5 = 60<br \/>\ntane olur.<br \/>\n\u00d6rnek 6:<br \/>\nBoyutlar\u0131 24 m ve 60 m olan dikd\u00f6rtgen \u015feklindeki bir arsan\u0131n \u00e7evresine e\u015fit aral\u0131klarla en az say\u0131da ka\u00e7 a\u011fa\u00e7 dikilebilir?<br \/>\n\u00c7\u00f6z\u00fcm:<br \/>\n\u0130ki a\u011fac\u0131n aras\u0131ndaki uzakl\u0131k, dikd\u00f6rtgenin boyutlar\u0131n\u0131n OBEB&#8217; i olur. Dolay\u0131s\u0131yla,<br \/>\n(24, 60)OBEB = 12<br \/>\nA\u011fa\u00e7 Say\u0131s\u0131 = \u00c7evre \/ 12 = 2 . (24 + 60) \/ 12 = 84 \/ 6 = 14<br \/>\ndir.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>OBEB (ORTAK B\u00d6LENLER\u0130N EN B\u00dcY\u00dc\u011e\u00dc) OBEB, iki veya daha \u00e7ok say\u0131y\u0131 ayn\u0131 anda b\u00f6lebilen en b\u00fcy\u00fck say\u0131d\u0131r. Verilen say\u0131lar\u0131n OBEB&#8217; ini bulmak i\u00e7in, say\u0131lar asal \u00e7arpanlar\u0131na ayr\u0131l\u0131r ve ortak asal \u00e7arpanlar\u0131n en k\u00fc\u00e7\u00fck \u00fcsleri al\u0131n\u0131r. 1. Aralar\u0131nda asal iki say\u0131n\u0131n OBEB&#8217; i 1&#8242; dir. Yani, a ile b aralar\u0131nda asal iki say\u0131 ise, (a, b)OBEB &hellip;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1404,1403],"tags":[7294,7295],"class_list":["post-3096","post","type-post","status-publish","format-standard","hentry","category-matematik-odevleri","category-odevler","tag-asal-carpanlar","tag-dikdortgenler-prizmasi"],"_links":{"self":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/3096","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/comments?post=3096"}],"version-history":[{"count":0,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/3096\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/media?parent=3096"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/categories?post=3096"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/tags?post=3096"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}