A. PROBLEM \u00c7\u00d6ZME STRATEJ\u0130S\u0130 Bir soruyu \u00e7\u00f6zmek i\u00e7in verilen zaman\u0131n % 75 ini soruyu anlamaya, % 17 sini \u00e7\u00f6zme yolunu olu\u015fturmaya % 8 ini de soruyu \u00e7\u00f6zmeye ay\u0131rmal\u0131s\u0131n\u0131z.
\nBuna g\u00f6re, sorular\u0131 \u00e7\u00f6zerken;
\n1) Soru, verilenler ve istenen anla\u015f\u0131lana kadar okunur.
\n2) Verilenler matematik diline \u00e7evrilir.
\n3) Denklem \u00e7\u00f6zme metodlar\u0131 ile matematik diline \u00e7evrilen denklem \u00e7\u00f6z\u00fcl\u00fcr.
\n4) Bulunan\u0131n, soru c\u00fcmlesinde istenen olup olmad\u0131\u011f\u0131 kontrol edilir.
\nB. MATEMAT\u0130K D\u0130L\u0130NE \u00c7EV\u0130RME
\nVerilen problemin x, y, a, b, c gibi sembollerle ifade edilmesine matematik diline \u00e7evirme denir.
\n1) Herhangi bir say\u0131 x olsun.
\nSay\u0131n\u0131n a fazlas\u0131 : x + a d\u0131r.
\nSay\u0131n\u0131n a fazlas\u0131n\u0131n yar\u0131s\u0131 :
\nSay\u0131n\u0131n yar\u0131s\u0131n\u0131n a fazlas\u0131 :
\nSay\u0131n\u0131n k\u00fcp\u00fcn\u00fcn a eksi\u011fi : x3 \u2013 a d\u0131r.
\n2) Herhangi iki say\u0131 x ve y olsun.
\nBu iki say\u0131n\u0131n toplam\u0131n\u0131n a kat\u0131 : a . (x + y) dir.
\nBu iki say\u0131n\u0131n kareleri toplam\u0131 : x2 + y2 dir.
\nBu iki say\u0131n\u0131n toplam\u0131n\u0131n karesi : (x + y)2 dir.
\n3) Ard\u0131\u015f\u0131k tam say\u0131lardan en k\u00fc\u00e7\u00fc\u011f\u00fc x olsun.
\nArd\u0131\u015f\u0131k \u00fc\u00e7 tam say\u0131n\u0131n toplam\u0131 :
\nx + (x + 1) + (x + 2) dir.
\nArd\u0131\u015f\u0131k \u00fc\u00e7 \u00e7ift say\u0131n\u0131n toplam\u0131 :
\nx + (x + 2) + (x + 4) t\u00fcr.
\nC. KES\u0130R PROBLEMLER\u0130
\na, b \u00ce Z ve b \u00b9 0 i\u00e7in ye kesir denir.
\nHerhangi bir say\u0131 x olsun.
\nBu say\u0131n\u0131n s\u0131 :
\nBu say\u0131n\u0131n s\u0131n\u0131n b fazlas\u0131 :
\nBu say\u0131s\u0131 kadar art\u0131r\u0131l\u0131rsa :
\nBu say\u0131n\u0131n si ile sinin toplam\u0131 :
\nD. YA\u015e PROBLEMLER\u0130
\nBir ki\u015finin ya\u015f\u0131 x ise,
\nT y\u0131l \u00f6nceki ya\u015f\u0131 : x \u2013 T
\nT y\u0131l sonraki ya\u015f\u0131 : x + T olur.
\nKi\u015filer aras\u0131ndaki ya\u015f fark\u0131 her zaman ayn\u0131d\u0131r.
\n\u0130ki ki\u015finin ya\u015flar\u0131 oran\u0131 y\u0131llara g\u00f6re orant\u0131l\u0131 de\u011fildir.
\n\u0130ki ki\u015finin ya\u015flar\u0131 toplam\u0131 T y\u0131l sonra 2T artar.
\nn ki\u015finin ya\u015flar\u0131 toplam\u0131 T y\u0131l sonra n . T artar.
\nE. \u0130\u015e\u00c7\u0130 – HAVUZ PROBLEMLER\u0130
\nBir i\u015fi;
\nA i\u015f\u00e7isi tek ba\u015f\u0131na a saatte,
\nB i\u015f\u00e7isi tek ba\u015f\u0131na b saatte,
\nC i\u015f\u00e7isi tek ba\u015f\u0131na c saatte
\nyapabiliyorsa;
\nA i\u015f\u00e7isi 1 saatte i\u015fin s\u0131n\u0131 bitirir.
\nA ile B birlikte t saatte i\u015fin sini bitirir.<\/p>\n
A, B, C birlikte t saatte i\u015fin sini bitirir.
\nE\u011fer \u00fc\u00e7\u00fc t saatte i\u015fi bitirmi\u015f ise bu ifade 1 e e\u015fittir.
\nA i\u015f\u00e7isi x saat, B i\u015f\u00e7isi y saat C i\u015f\u00e7isi z saat \u00e7al\u0131\u015farak i\u015fi bitiriyorsa,<\/p>\n
Havuz problemleri i\u015f\u00e7i problemleri gibi \u00e7\u00f6z\u00fcl\u00fcr.
\nA muslu\u011fu havuzun tamam\u0131n\u0131 a saatte doldurabiliyor.
\nTabanda bulunan B muslu\u011fu dolu havuzun tamam\u0131n\u0131 tek ba\u015f\u0131na b saatte bo\u015faltabiliyor olsun.
\nBu iki musluk birlikte bu havuzun t saatte
\nsini doldurur.
\nBu havuzun dolmas\u0131 i\u00e7in b > a olmal\u0131d\u0131r.
\nF. HAREKET PROBLEMLER\u0130
\nV : Hareketlinin h\u0131z\u0131
\nx : Hareketlinin V h\u0131z\u0131yla t s\u00fcrede ald\u0131\u011f\u0131 yol
\nt : Hareketlinin V h\u0131z\u0131yla x yolunu alma s\u00fcresi ise,
\n Aralar\u0131nda x km olan iki ara\u00e7 saatte V1 km ve V2 km h\u0131zla ayn\u0131 anda birbirine do\u011fru hareket ederlerse kar\u015f\u0131la\u015fma s\u00fcresi
\n Bu iki ara\u00e7 ayn\u0131 anda \u00e7embersel bir pistin, ayn\u0131 noktas\u0131ndan z\u0131t y\u00f6nde ayn\u0131 anda hareket ederlerse kar\u015f\u0131la\u015fma s\u00fcresi yine <\/p>\n
Aralar\u0131nda x km olan iki ara\u00e7 saatte V1 km ve V2 km h\u0131zla ayn\u0131 anda ayn\u0131 y\u00f6nde hareket ederlerse arkadaki arac\u0131n (V1 h\u0131zl\u0131 ara\u00e7) \u00f6ndekini yakalama s\u00fcresi<\/p>\n
Bu iki ara\u00e7 ayn\u0131 anda \u00e7embersel bir pistin ayn\u0131 noktas\u0131ndan ayn\u0131 y\u00f6nde hareket ederse h\u0131z\u0131 b\u00fcy\u00fck olan arac\u0131n h\u0131z\u0131 k\u00fc\u00e7\u00fck olan arac\u0131
\nyakalama s\u00fcresi yine<\/p>\n
E\u015fit zamanda V1 ve V2 h\u0131zlar\u0131yla al\u0131nan yolda hareketlinin ortalama h\u0131z\u0131,
\nBelirli bir yolu V1 h\u0131z\u0131yla gidip V2 h\u0131z\u0131yla d\u00f6nen bir arac\u0131n ortalama h\u0131z\u0131,
\nG. Y\u00dcZDE PROBLEMLER\u0130
\nA say\u0131s\u0131n\u0131n % a s\u0131 :
\nA n\u0131n % a s\u0131 ile B nin % b sinin toplam\u0131 :<\/p>\n
A ya A n\u0131n % a s\u0131 eklenirse :<\/p>\n
A dan A n\u0131n % a s\u0131 \u00e7\u0131kar\u0131l\u0131rsa :<\/p>\n
H. FA\u0130Z PROBLEMLER\u0130
\nF : Faiz miktar\u0131
\nA : Ana para (Kapital)
\nn : Y\u0131ll\u0131k faiz oran\u0131
\nt : Kapitalin faizde kalma s\u00fcresi
\nolmak \u00fczere,
\nt y\u0131lda,t ayda,t g\u00fcnde,Faize yat\u0131r\u0131lan para her y\u0131l getirdi\u011fi faiz ile birlikte tekrar faize yat\u0131r\u0131l\u0131rsa elde edilen toplam faize bile\u015fik faiz denir.
\nBuna g\u00f6re, A TL y\u0131ll\u0131k bile\u015fik faiz oran\u0131 % n olan bir bankaya yat\u0131r\u0131l\u0131yor. t y\u0131l sonra<\/p>\n
I. KARI\u015eIM PROBLEMLER\u0130<\/p>\n
A kab\u0131nda, tuz oran\u0131 % A olan x litrelik tuzlu su \u00e7\u00f6zeltisi ile B kab\u0131nda tuz oran\u0131 % B olan y litrelik tuzlu su \u00e7\u00f6zeltisi, bo\u015f olan C kab\u0131nda kar\u0131\u015ft\u0131r\u0131l\u0131rsa olu\u015fan x + y litrelik kar\u0131\u015f\u0131m\u0131n tuz oran\u0131
\n\u00ae Tuz oran\u0131 % A olan tuzlu su \u00e7\u00f6zeltisinin su oran\u0131 % (100 \u2013 A) d\u0131r<\/p>\n","protected":false},"excerpt":{"rendered":"
A. PROBLEM \u00c7\u00d6ZME STRATEJ\u0130S\u0130 Bir soruyu \u00e7\u00f6zmek i\u00e7in verilen zaman\u0131n % 75 ini soruyu anlamaya, % 17 sini \u00e7\u00f6zme yolunu olu\u015fturmaya % 8 ini de soruyu \u00e7\u00f6zmeye ay\u0131rmal\u0131s\u0131n\u0131z. Buna g\u00f6re, sorular\u0131 \u00e7\u00f6zerken; 1) Soru, verilenler ve istenen anla\u015f\u0131lana kadar okunur. 2) Verilenler matematik diline \u00e7evrilir. 3) Denklem \u00e7\u00f6zme metodlar\u0131 ile matematik diline \u00e7evrilen denklem \u00e7\u00f6z\u00fcl\u00fcr. …<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1404,1403],"tags":[7361,7360],"class_list":["post-3142","post","type-post","status-publish","format-standard","hentry","category-matematik-odevleri","category-odevler","tag-denklem-cozme-metodlari","tag-denklem-kurma-problemleri"],"_links":{"self":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/3142","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/comments?post=3142"}],"version-history":[{"count":0,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/3142\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/media?parent=3142"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/categories?post=3142"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/tags?post=3142"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}