TAM SAYILARDA \u00c7ARPMA \u0130\u015eLEM\u0130
\n (+2).(+5)=(+10) ; (+2).(-5)=(+10)
\n Ayn\u0131 i\u015faretli iki say\u0131n\u0131n \u00e7arp\u0131m\u0131
\n (+2).(-5)=(-10) ; (-2)+5)=(-10)
\n Ters i\u015faretli iki tam say\u0131y\u0131 \u00e7arpmak i\u00e7in say\u0131lar\u0131n mutlak de\u011ferleri \u00e7arp\u0131l\u0131r ve \u00e7arp\u0131m\u0131n \u00f6n\u00fcne (-) i\u015fareti yaz\u0131l\u0131r.
\n \u00d6zetlersek, ayn\u0131 i\u015faretli tam say\u0131lar\u0131n \u00e7arp\u0131m\u0131 pozitif, ters i\u015faretli say\u0131lar\u0131n \u00e7arp\u0131m\u0131 negatif bir tam say\u0131d\u0131r.
\n TAMSAYILARDA \u00c7ARPMA \u0130\u015eLEM\u0130NDE 1\u2019\u0130N ETK\u0130S\u0130
\n A\u015fa\u011f\u0131daki \u00f6rnekleri inceleyiniz.<\/p>\n
a)(+1).(+7)=(+7).(+1)=(+7)\u2019d\u0131r.
\n b)(+1).( -9)=(-9).(+1)=(-9) \u2018dur.
\n c)(+1).0=0.(+1)=0\u2019d\u0131r
\n Herhangi bir say\u0131n\u0131n (+1) tam say\u0131s\u0131 ile \u00e7arp\u0131m\u0131 o tam say\u0131n\u0131n kendisidir.
\n +1 say\u0131s\u0131 tam say\u0131lar k\u00fcmesinde etkisiz elemand\u0131r.
\n TAM SAYILAR K\u00dcMES\u0130NDE 0\u2019IN ETK\u0130S\u0130
\n A\u015fa\u011f\u0131daki \u00f6rnekleri inceleyiniz.<\/p>\n
a)0.(+5)=(+5).0=0\u2019d\u0131r
\n b)0.(-4)=(-4).0=0 d\u0131r.
\n Yukar\u0131daki \u00f6rneklerde oldu\u011fu gibi, herhangi bir tam say\u0131n\u0131n 0 (s\u0131f\u0131r) ile \u00e7arp\u0131m\u0131 0\u2019d\u0131r.
\n Tam say\u0131lar k\u00fcmesinde 0 \u00e7arpma i\u015flemine g\u00f6re yutan elemand\u0131r.<\/p>\n
\u00dc\u00c7 VEYA DAHA FAZLA SAYININ \u00c7ARPIMINI BULMAK<\/p>\n
1) (+3).(-4).(+5)= i\u015fleminin yap\u0131l\u0131\u015f\u0131n\u0131 inceleyiniz.<\/p>\n
(+3).(-4).(+5)=[(+3).(-4)].(+5)
\n =(-12).(+5)
\n = (-60)
\n Ayn\u0131 i\u015flemi bir de a\u015fa\u011f\u0131da oldu\u011fu gibi yapal\u0131m.<\/p>\n
(+3).(-4).(+5)=(+3).[(-4).(+5)]
\n =(+3).(-20)
\n =(-60)
\n 2) (+2).(-3).(+5).(-5)= i\u015fleminin yap\u0131l\u0131\u015f\u0131n\u0131 inceleyiniz.<\/p>\n
(+2).(-3).(+5).(-5)=[(+2).(-3)].[(+5).(-5)]
\n =(-6).(-25)
\n = -150
\n Ayn\u0131 i\u015flemi birde a\u015fa\u011f\u0131da oldu\u011fu gibi de\u011fi\u015fik grupland\u0131rma ile yapal\u0131m<\/p>\n
(+2).(-3).(+5).(-5)=[(+2).(+5)].[(-3).(-5)]
\n =(+10).(-15)
\n =(-150)
\n \u00dc\u00e7 veya daha fazla tam say\u0131y\u0131 de\u011fi\u015fik grupland\u0131rmad\u0131r yaparak \u00e7arparsak, \u00e7arp\u0131m de\u011fi\u015fmez.<\/p>\n
ALI\u015eTIRMALAR<\/p>\n
1)A\u015fa\u011f\u0131daki \u00e7arpma i\u015flemlerini yap\u0131n\u0131z.
\n a)(+2).(+2).(+2)=[(+2).(+2)].(+2)
\n =(+4).(+2)
\n =(+6)
\n b)(-3).(-3).(-3).(-3)=[(-3).(-3)].[(-3).(-3)]
\n =(-6).(-6)
\n =36
\n c) (+5).(+5)=25
\n d)(+40).(+40).(+40)=[(+40).(+40)].(+40)
\n =(+160).(+40)
\n =(+6400)
\n e) (-2).(+19)=(-38) f) (+25).(+12)=(+300)
\n g)(+3).(-6).(-4).(-5)=[(+3).(-6)].[(-4).(-5)]
\n =(-18).(+20)
\n =(-360)
\n h) (+6).(+6).(-5).(-1)=[ (+6).(+6)].[(-5).(-1)]
\n =(+36).(+5)
\n =(+180)
\n 2)A\u015fa\u011f\u0131da \u00e7arpma i\u015flemini yap\u0131n\u0131z.
\n a)(+7).(+3)=(+21)
\n b)(-4).(-9)=(+36)
\n c)(-5).(+10)=(-50)
\n d)(+12).(-6)=(-72)
\n e)(-7).(-5)=(+35)
\n f)(-13).(-1)=(+13)
\n 3)A\u015fa\u011f\u0131da \u00e7arpma i\u015flemlerini yap\u0131n\u0131z.
\n a)(+3).(-7).(-5)=(+3).[(-7).(-5)]
\n =(+3).(+35)
\n =(+105)
\n b)(-8).(+7).(-2)=[(-8).(-2)].(+7)
\n =(+16).(+7)
\n =(+112)
\n c)(-2).(-1).(+3).(-4)=[(-2).(-1).(-4)].(+3)
\n =(+8).(+3)
\n (+24)
\n d)(+9).(-5).(-7).0=0<\/p>\n
4) A\u015fa\u011f\u0131daki \u00e7arpma i\u015flemlerinde verilmeyeni bulunuz.<\/p>\n
a) (+4).(?)=(+24)
\n (+24)+4)=(+6)
\n (+4).(+6)=(+24)
\n b) (-7).(?)=(+56)
\n (-56)-7)=(-8)
\n (-7).(-8)=(+56)
\n c) (?).(-9)=(-63)
\n (-63)-9)=(+7)
\n (+7).(-9)=(-63)
\n d) (?).(+8)=(-72)
\n (-72)+8)=(-9)
\n (-9).(+8)=(-72)
\n 5) A\u015fa\u011f\u0131daki \u00e7arpma i\u015flemlerinde verilmeyeni bulunuz.<\/p>\n
a) (?).(+7)=(+7)
\n (+7)+1)=(+7)
\n (+1).(+7)=(+7)
\n b) (?).(+45)=0
\n 0+45)=0
\n 0.(+45)=0
\n c)(+2).(-3).(?)=(-24)
\n (-24)+2)=(-12)
\n (-12)-3)=(+4)
\n (+2).(-3).(+4)=(-24)
\n d) (-19).(?)=(-19
\n (-19).(+1)=(-19)
\n (-19).(+1)=(-19)
\n e) (-54).(?)=(-54)
\n (+54)-1)=(-54)
\n (+54).(-1)=(-54)
\n f) (?).(-5).(-2)=(+80)
\n (+80)-2)=(-40)
\n (-40)-5)=(+8)
\n (+8).(-5).(-2)=(-80)
\n 6)A\u015fa\u011f\u0131daki i\u015flemleri yap\u0131n\u0131z.<\/p>\n
a) (+3).[(-2).(-8)] b)(-5).[(+9).(-4)]
\n =(+3).(+16)=(+48) =(-5).(-36)=(-180)<\/p>\n
c) [(+8).(-39].(-69)= d) [(+2).(+7)].(-14)=
\n =(-24).(-6) =(+14).(-14)
\n =(+144) =(-196)<\/p>\n
7)A\u015fa\u011f\u0131daki i\u015flemleri yap\u0131n\u0131z.<\/p>\n
a) (+7).(-6).(+7).(-4)=[(+7).(+7)].[(-6).(-4)]
\n =(+49).(+24)
\n =1176
\n b) (+7).[(-6).(-4)]=(+7).(+24)
\n =168
\n c) (-4).(+7).(-3).(+5)=[(+7).(+5)].[(-4).(-3)]
\n =(+35).(+12)
\n =420
\n d) [(-6).(-4)].[(+2).(+7)]=(+24).(+14)
\n = 336
\n 8)A\u015fa\u011f\u0131daki sorular\u0131 cevaplay\u0131n\u0131z.
\n a) [(-9).(-4)].[(+2).(+7)]=(+36).(+14)
\n =504
\n b) [(-9).(-4)].[(+8).(-3)]=(+36).(-24)
\n =(-864)
\n c) [(-2).(-8)].[(+2).(+7)]=(+16).(+14)
\n =(+224)
\n d) [(-9).(-4)].[(+2).(+7)]=(+36).(+14)
\n =(+504)
\n 9)A\u015fa\u011f\u0131daki sorular\u0131 cevaplay\u0131n\u0131z.<\/p>\n
a) [(-6).(-4)].[(+8).(+3)]=(+24).(+24)
\n = (+24)
\n b) [(-2).(8)].[(+8).(+3)]=(+16).(+24)
\n =(+384)
\n c) (-9).(-4)].[(+4).(+6)]=(+36).(+24)
\n =(+864)
\n d) [(-6).(-4)].[(+2).(+8)]=(+24).(+16)
\n =(+384)
\n e) [(-6).(-4)].[(+9).(+4)]=(+24).(+36)
\n =(+864)
\n 10)
\n a) [(+7).(-3).(-5)].(-32)=(-105).(-32)
\n =(+3360)
\n b) [(-4).(-3)].[(+2).(-14)]=(+12).(-28)
\n =(-336)
\n c) [(+9).(-12)].[(-4).(-2)]=(-108).(+6)
\n =(-636)
\n d) [(+6).(-4)].[(+7).(+4)]=(-24).(+28)
\n =(-672)<\/p>\n
TAM SAYILAR K\u00dcMES\u0130NDE B\u00d6LME \u0130\u015eLEM\u0130 <\/p>\n
B\u00f6lme Kavram\u0131:
\n 1) (+5).(-3)=(-15) oldu\u011funu tam say\u0131lar\u0131n \u00e7arp\u0131m\u0131na ait kuraldan biliyoruz.\u015eimdi,
\n (+5).n=(-15) e\u015fitli\u011fini sa\u011flayan n say\u0131s\u0131n\u0131 bulal\u0131m Ba\u015fka bir deyi\u015fle, (+5) ile \u00e7arp\u0131ld\u0131\u011f\u0131nda (-15) tam say\u0131s\u0131n\u0131 veren say\u0131y\u0131 bulaca\u011f\u0131z.
\n n=(-3) oldu\u011funu hemen ak\u0131ldan s\u00f6yleyebiliriz.
\n Bu e\u015fitli\u011fi sa\u011flayan n=(-3) tam say\u0131s\u0131na (-15) tam say\u0131s\u0131n\u0131n (+5) tam say\u0131s\u0131na b\u00f6l\u00fcm\u00fc denir ve
\n n=(-15)+5)=(-3) bi\u00e7iminde g\u00f6sterilir.
\n Bu i\u015flemde (-15)\u2019e b\u00f6l\u00fcnen, (+5)\u2019e b\u00f6len, (-3)\u2019e b\u00f6l\u00fcm denir.
\n Negatif bir say\u0131n\u0131n pozitif bir say\u0131ya b\u00f6l\u00fcm\u00fc negatif bir say\u0131d\u0131r.
\n Kalans\u0131z bir b\u00f6lme i\u015fleminde her zaman;
\n B\u00f6l\u00fcnen=b\u00f6len . b\u00f6l\u00fcm e\u015fitli\u011fi do\u011fru olur.
\n 2) \u015eimdi de (+24)-4) b\u00f6lme i\u015flemini yapal\u0131m.Bu b\u00f6lme i\u015fleminin sonucunu bulmak i\u00e7in (-4)ile \u00e7arp\u0131ld\u0131\u011f\u0131nda (+24) say\u0131s\u0131n\u0131 veren say\u0131y\u0131 bulmal\u0131y\u0131z.
\n (-6).(-4)=+24 oldu\u011funa g\u00f6re;
\n (+24)-4)=(-6)
\n Bu \u00f6rnekte oldu\u011fu gibi pozitif bir say\u0131n\u0131n negatif bir say\u0131ya b\u00f6l\u00fcm\u00fc negatif bir say\u0131d\u0131r.
\n 3) Yukar\u0131daki b\u00f6lme i\u015flemlerinde oldu\u011fu gibi d\u00fc\u015f\u00fcn\u00fcl\u00fcrse;
\n (+28)+7)=(+4)t\u00fcr \u00e7\u00fcnk\u00fc (+4).(+7)=(+28)
\n (-28)-7)=(+4)t\u00fcr \u00e7\u00fcnk\u00fc (+4).(-7)=(-28)
\n Ayn\u0131 i\u015faretli iki say\u0131n\u0131n b\u00f6l\u00fcm\u00fc pozitiftir.
\n \u00d6zetlersek; ayn\u0131 i\u015faretli iki say\u0131n\u0131n b\u00f6l\u00fcm\u00fc pozitif(+), Ters i\u015faretli iki say\u0131n\u0131n b\u00f6l\u00fcm\u00fc negatif(-)tir.
\n Tamsay\u0131lar\u0131n (+1)ve (-1) Say\u0131lar\u0131 ile B\u00f6lme \u0130\u015flemi
\n 1)(+8)+1)=(+8)dir\u00c7\u00fcnk\u00fc (+1).(+8)=(+8)d\u0131r.
\n (-7)-1)=(-7)d\u0131r.\u00c7\u00fcnk\u00fc (-1).(-7)=(-7)d\u0131r.
\n Bir tam say\u0131n\u0131n (+1) say\u0131s\u0131na b\u00f6l\u00fcm\u00fc o tam say\u0131n\u0131n kendisidir.
\n Bu \u00f6zelik b\u00fct\u00fcn tam say\u0131lar i\u00e7in do\u011frudur.
\n 2)(-6)-1)=(-6)d\u0131r.\u00c7\u00fcnk\u00fc, (-1).(-6)=(-6)d\u0131r.
\n (-9)-1)=(-9)dur.\u00c7\u00fcnk\u00fc, (-1).(-9)=(-9)dur.
\n Bir tam say\u0131n\u0131n (-1) say\u0131s\u0131na b\u00f6l\u00fcm\u00fc, o tam say\u0131n\u0131n toplama i\u015flemine g\u00f6re tersidir.
\n S\u0131f\u0131r Say\u0131s\u0131 ve B\u00f6lme \u0130\u015flemi:
\n 1) 0+4) i\u015fleminin sonucunu bulal\u0131m.
\n (+4).0= oldu\u011fundan 0+4)=0d\u0131r.
\n 2) 0-7) i\u015fleminin sonucunu bulal\u0131m.
\n (-7).0=0 oldu\u011fundan 0-7)=0 d\u0131r.S\u0131f\u0131r\u0131n, s\u0131f\u0131rdan farkl\u0131 bir tam say\u0131ya b\u00f6l\u00fcm\u00fc s\u0131f\u0131rd\u0131r.
\n 3)(+8):0 i\u015fleminin anlam\u0131 yoktur.\u00c7\u00fcnk\u00fc hi\u00e7 bir say\u0131n\u0131n 0 ile \u00e7arp\u0131m\u0131 (+8) say\u0131s\u0131na e\u015fit de\u011fildir.
\n 4)0:0 i\u015fleminin de anlam\u0131 yoktur.\u00c7\u00fcnk\u00fc her tam say\u0131n\u0131n 0 ile \u00e7arp\u0131m\u0131 s\u0131f\u0131ra e\u015fittir.Bunun i\u00e7in 0:0 b\u00f6lmesinin belli bir de\u011feri yoktur.
\n Sonu S\u0131f\u0131rl\u0131 Tam Say\u0131lar\u0131 10 ve 10 un Kuvvetlerine K\u0131sa Yoldan B\u00f6lme:
\n 1) a)(+370)+10)=+37
\n b)(-8200)+100)=-82
\n c)(+35000)+1000)=+35 olur.
\n 2) a)(+400)-10)=(-40)
\n b)(-7300)-100)=+73
\n c)(+80000)+10000)=(-8) olur.
\n Sonu s\u0131f\u0131rl\u0131 tam say\u0131lar\u0131 10,100,1000,… ile k\u0131sa yoldan b\u00f6lmek i\u00e7in b\u00f6l\u00fcnenin sonundan s\u0131ra ile 1,2,3,… s\u0131f\u0131r sileriz.
\n \u00d6rnekler
\n 1)a) (-12)-3)=+4 b)(+75)+3)=+25
\n c)(-48)+8)=(-6) d)(+126)-7)=(-18)
\n 2)[(-36)+4)]:[(+9)-3)]=(-9)-3)
\n =(+3)
\n \u00c7\u00f6z\u00fcml\u00fc \u00d6rnekler
\n 1) A\u015fa\u011f\u0131daki b\u00f6lme i\u015flemlerini yap\u0131n\u0131z.<\/p>\n
a)(+21)+7)=(+3) b)(+35)-5)=(-7)
\n c)(-24)-8)=+3 c)(-25)+5)=(-5)
\n 2) A\u015fa\u011f\u0131daki b\u00f6lme i\u015flemlerini yap\u0131n\u0131z.<\/p>\n
a)0+7)=0 b)0-8)=0
\n c)0:0=belirsizdir.B\u00f6l\u00fcm yoktur.
\n d)(+6):0= s\u0131f\u0131ra b\u00f6l\u00fcm tan\u0131ms\u0131zd\u0131r.B\u00f6l\u00fcm yoktur.
\n 3)A\u015fa\u011f\u0131daki b\u00f6lme i\u015flemlerini yapal\u0131m.<\/p>\n
a)(+15)+1)=(+15) b)(-45)+1)=(-45)
\n c)(+1)+1)=(+1) d)(-1)+1)=(-1)
\n 4)A\u015fa\u011f\u0131daki e\u015fitliklerde, yerine yaz\u0131lacak say\u0131lar\u0131 bulunuz.
\n a) +7)=(+5) c) -3)=(+7)
\n b)(+12): =(-4) d)(+8)-2)= <\/p>\n
\u00c7\u00f6z\u00fcmler:
\n a) =(+7).(+5)=35 b) =(+7).(-3)=(-21)
\n c) =(+12)-4)=(3) c) =(+8)-2)=(-4)<\/p>\n","protected":false},"excerpt":{"rendered":"
TAM SAYILARDA \u00c7ARPMA \u0130\u015eLEM\u0130 (+2).(+5)=(+10) ; (+2).(-5)=(+10) Ayn\u0131 i\u015faretli iki say\u0131n\u0131n \u00e7arp\u0131m\u0131 (+2).(-5)=(-10) ; (-2)+5)=(-10) Ters i\u015faretli iki tam say\u0131y\u0131 \u00e7arpmak i\u00e7in say\u0131lar\u0131n mutlak de\u011ferleri \u00e7arp\u0131l\u0131r ve \u00e7arp\u0131m\u0131n \u00f6n\u00fcne (-) i\u015fareti yaz\u0131l\u0131r. \u00d6zetlersek, ayn\u0131 i\u015faretli tam say\u0131lar\u0131n \u00e7arp\u0131m\u0131 pozitif, ters i\u015faretli say\u0131lar\u0131n \u00e7arp\u0131m\u0131 negatif bir tam say\u0131d\u0131r. TAMSAYILARDA \u00c7ARPMA \u0130\u015eLEM\u0130NDE 1\u2019\u0130N ETK\u0130S\u0130 A\u015fa\u011f\u0131daki \u00f6rnekleri inceleyiniz. …<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1404,1403],"tags":[10018,10019,7504,10016,10017],"class_list":["post-4616","post","type-post","status-publish","format-standard","hentry","category-matematik-odevleri","category-odevler","tag-carpma-islemleri","tag-negatif","tag-tam-sayi","tag-tam-sayilarda-carpma-ve-bolme-islemi","tag-ters-isaret"],"_links":{"self":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/4616","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/comments?post=4616"}],"version-history":[{"count":0,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/4616\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/media?parent=4616"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/categories?post=4616"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/tags?post=4616"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}