Mol : Avagadro say\u0131s\u0131 ( 6,02.1023 ) kadar atom yada molek\u00fcl i\u00e7eren maddeye 1 mol denir.<\/p>\n
\u00d6rnek : 1 mol HF 6,02.1023 tane HF molek\u00fcl\u00fcd\u00fcr. Yine bu molek\u00fcl\u00fcn i\u00e7erisinde 1 mol H atomu (6,02.1023tane) ve 1 mol F atomu (6,02.1023 tane) vard\u0131r.<\/p>\n
Atom A\u011f\u0131rl\u0131\u011f\u0131 : 12C izotopu standart se\u00e7ilerek di\u011fer elementlerin bu izotopla k\u0131yaslanmas\u0131 sonucu hesaplanan k\u00fctlelerdir. \u00d6rne\u011fin, H=1 O=16 N=14 S=32<\/p>\n
1 Atomik K\u00fctle Birimi (a.k.b) : 1\/ 6,02.1023 = 1,66.10-24 gramd\u0131r.<\/p>\n
Molek\u00fcl A\u011f\u0131rl\u0131\u011f\u0131 : Bile\u015fi\u011fi olu\u015fturan elementlerin gram cinsinden k\u00fctlelerinin toplam\u0131na denir.<\/p>\n
\u00d6rnek : 1 mol C6H12O6 (glikoz) ka\u00e7 gramd\u0131r ? (C=12 O=16 H=1)<\/p>\n
6.12 = 72 gram C
\n 12.1 = 12 gram H
\n 6.16 = 96 gram O
\n ——————————-
\n 180 gram<\/p>\n
Bir Tane Molek\u00fcl\u00fcn K\u00fctlesi : Bir tek molek\u00fcl\u00fcn k\u00fctlesi molek\u00fcl a\u011f\u0131rl\u0131\u011f\u0131n\u0131n Avagadro say\u0131s\u0131na b\u00f6l\u00fcm\u00fcyle bulunur .
\n 1 tek molek\u00fcl\u00fcn k\u00fctlesi = MA\/6,02.1023<\/p>\n
\u00d6rnek : 1 tane H2O molek\u00fcl\u00fc ka\u00e7 gramd\u0131r ? (H=1 O=16)<\/p>\n
1 tane H2O = 18\/ 6.1023 = 3.10-23 gramd\u0131r.
\n Bir Tane Atomun K\u00fctlesi : Atom a\u011f\u0131rl\u0131\u011f\u0131n\u0131n Avagadro say\u0131s\u0131na oran\u0131d\u0131r.
\n 1 tek atomun k\u00fctlesi = A.A.\/ 6,02.1023
\n \u00f6rnek : 1 tane C atomu ka\u00e7 gramd\u0131r ? (C=12)
\n 1 tane C atomu = 12\/6.1023 = 2.10-23 gramd\u0131r.
\n N.\u015e.A\u2019 da Hacim : B\u00fct\u00fcn gazlar\u0131n bir mol\u00fc N.\u015e.A\u2019da ( 0 0C ve 1 atmosfer de) 22,4 litredir.<\/p>\n
Mol Hesaplama Y\u00f6ntemleri :
\n m Verilen Litre Verilen tanecik Say\u0131s\u0131
\n n= n= n=
\n MA 22,4 6,02.1023
\n \u00d6rnek : 23 gram C2H5OH ka\u00e7 mold\u00fcr ? (C=12 O=16 H =1)
\n MA = 2.12 + 6.1 + 16.1= 46 gram\/mol
\n n=23\/46 = 0,5 mol
\n \u00d6rnek : N.\u015e.A\u2019da 2,8 litre olan CO2 gaz\u0131 ka\u00e7 mol ve ka\u00e7 gramd\u0131r ?(C=12 O=16)
\n n=2,8\/22,4 = 0,125 mol.
\n 1 mol CO2 44 gram oldu\u011funa g\u00f6re 0,125 mol CO2 0,125.44= 5,5 gramd\u0131r.
\n 22,4 litre = 1 mol : 11,2 litre= 0,5 mol : 5,6 litre = 0,25 mol : 2,8 Litre = 0,125 mol<\/p>\n
\u00d6rnek : 3,01.1023 tane C2H4 molek\u00fcl\u00fc ka\u00e7 gramd\u0131r ? (C=12 H=1)
\n n=3,01.1023\/6,02.1023= 0,5 mol 1 mol C2H4 28 gram ise 0,5 mol C2H4 14 gram olur.<\/p>\n
K\u00fctlece y\u00fczde = (Elementin bile\u015fikteki k\u00fctlesi\/toplam k\u00fctle)x100
\n I. elementin bile\u015fikteki k\u00fctlesi I. elementin verilen gram\u0131
\n =
\n II. elementin bile\u015fikteki k\u00fctlesi II. elementin verilen gram\u0131<\/p>\n
I. elementin bile\u015fikteki k\u00fctlesi I. elementin verilen y\u00fczdesi
\n =
\n II. elementin bile\u015fikteki k\u00fctlesi II. elementin verilen y\u00fczdesi<\/p>\n","protected":false},"excerpt":{"rendered":"
Mol : Avagadro say\u0131s\u0131 ( 6,02.1023 ) kadar atom yada molek\u00fcl i\u00e7eren maddeye 1 mol denir. \u00d6rnek : 1 mol HF 6,02.1023 tane HF molek\u00fcl\u00fcd\u00fcr. Yine bu molek\u00fcl\u00fcn i\u00e7erisinde 1 mol H atomu (6,02.1023tane) ve 1 mol F atomu (6,02.1023 tane) vard\u0131r. Atom A\u011f\u0131rl\u0131\u011f\u0131 : 12C izotopu standart se\u00e7ilerek di\u011fer elementlerin bu izotopla k\u0131yaslanmas\u0131 sonucu …<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1407,1403],"tags":[2796,11575,2195,2194,2196],"class_list":["post-6152","post","type-post","status-publish","format-standard","hentry","category-fen-ve-teknoloji-odevleri","category-odevler","tag-atmosfer","tag-atom-agirligi","tag-avagadro-sayisi","tag-mol-kavrami","tag-molekul"],"_links":{"self":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/6152","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/comments?post=6152"}],"version-history":[{"count":0,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/6152\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/media?parent=6152"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/categories?post=6152"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/tags?post=6152"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}