{"id":6321,"date":"2012-04-03T11:19:52","date_gmt":"2012-04-03T08:19:52","guid":{"rendered":"http:\/\/www.islamidavet.com\/kutuphane\/\/?p=6321"},"modified":"2012-04-03T11:19:52","modified_gmt":"2012-04-03T08:19:52","slug":"basinc-2","status":"publish","type":"post","link":"https:\/\/www.islamidavet.com\/kutuphane\/basinc-2\/","title":{"rendered":"Bas\u0131n\u00e7"},"content":{"rendered":"<p> Kat\u0131 S\u0131v\u0131 ve Gazlar a\u011f\u0131rl\u0131klar\u0131 nedeniyle bulunduklar\u0131 y\u00fczeye bir kuvvet uygularlar. Kuvvetin kayna\u011f\u0131 ne olursa olsun birim y\u00fczeye dik olarak etki eden kuvvete bas\u0131n\u00e7(P), b\u00fct\u00fcn y\u00fczeye dik olarak etki eden kuvvete de Bas\u0131n\u00e7 kuvveti(F) denir.<br \/>\n Bas\u0131n\u00e7 ile bas\u0131n\u00e7 kuvveti aras\u0131nda; P=F\/S ba\u011f\u0131nt\u0131s\u0131 vard\u0131r.<\/p>\n<p> Kat\u0131larda Bas\u0131n\u00e7<br \/>\n Kat\u0131 cisimler a\u011f\u0131rl\u0131klar\u0131 nedeniyle bulunduklar\u0131 y\u00fczeye bas\u0131n\u00e7 yaparlar. Taban alan\u0131 S, a\u011f\u0131rl\u0131\u011f\u0131 G olan kat\u0131 bir cisim, bulundu\u011fu y\u00fczeye; P=h.d kadar bir bas\u0131n\u00e7 uygularlar. <\/p>\n<p> 1.Kat\u0131larda bas\u0131n\u00e7 kuvveti daima kat\u0131n\u0131n a\u011f\u0131rl\u0131\u011f\u0131 kadard\u0131r. Dolay\u0131s\u0131yla kat\u0131 cismi hangi y\u00fczeyi \u00fczerine koyarsak koyal\u0131m bas\u0131n\u00e7 kuvveti de\u011fi\u015fmez. <\/p>\n<p> 2.D\u00fczg\u00fcn kat\u0131lar\u0131n (k\u00fcp, dikd\u00f6rtgenler prizmas\u0131, silindir) zemine yapt\u0131klar\u0131 bas\u0131n\u00e7 P=h.d ile de hesaplanabilir. Burada h cismin y\u00fcksekli\u011fi, d ise \u00f6zk\u00fctlesidir.<\/p>\n<p> 3.Kat\u0131lar uygulanan kuvveti kendi do\u011frultusunda aynen iletirken, Bas\u0131nc\u0131 aynen iletmezler. Kat\u0131larda bas\u0131n\u00e7 genel olarak y\u00fczeyle ters orant\u0131l\u0131d\u0131r. Bundan yararlanarak kesici ve delici Aletler yap\u0131l\u0131r.<\/p>\n<p> Birimi N\/m2=Pascal, dyn\/cm2=Bar <\/p>\n<p> S\u0131v\u0131larda Bas\u0131n\u00e7<br \/>\n Bir kaptaki s\u0131v\u0131 a\u011f\u0131rl\u0131\u011f\u0131 nedeniyle bulundu\u011fu kab\u0131n her noktas\u0131na bas\u0131n\u00e7 uygular.<br \/>\n S\u0131v\u0131 i\u00e7indeki herhangi bir noktadaki s\u0131v\u0131 bas\u0131nc\u0131;<\/p>\n<p> 1.S\u0131v\u0131n\u0131n yo\u011funlu\u011fu ile do\u011fru orant\u0131l\u0131d\u0131r.<br \/>\n 2.S\u0131v\u0131n\u0131n \u00fcst y\u00fczeyine olan uzakl\u0131kla do\u011fru orant\u0131l\u0131d\u0131r.<br \/>\n 3.S\u0131v\u0131n\u0131n derinli\u011fi ayn\u0131 kalmak \u015fart\u0131yla kab\u0131n \u015fekline ve i\u00e7indeki s\u0131v\u0131 miktar\u0131na ba\u011fl\u0131 de\u011fildir. <\/p>\n<p> S\u0131v\u0131 bas\u0131n\u00e7 kuvveti<br \/>\n (F): Bir S\u0131v\u0131n\u0131n a\u011f\u0131rl\u0131\u011f\u0131 nedeniyle i\u00e7inde bulundu\u011fu kab\u0131n herhangi bir y\u00fczeyinin tamam\u0131na uygulad\u0131\u011f\u0131 dik kuvvete s\u0131v\u0131 bas\u0131n\u00e7 kuvveti denir. Bu kuvvet;F=h.d.S<\/p>\n<p> H:ilgili y\u00fczeyin orta noktas\u0131n\u0131n s\u0131v\u0131n\u0131n \u00fcst y\u00fczeyine uzakl\u0131\u011f\u0131<br \/>\n D:s\u0131v\u0131n\u0131n \u00f6zk\u00fctlesi<br \/>\n S:ilgili y\u00fczeyin alan\u0131d\u0131r.<br \/>\n \u015eekildeki gibi bir kap i\u00e7inde h y\u00fcksekli\u011finde d \u00f6zk\u00fctleli s\u0131v\u0131 varsa S1, S2, S3 y\u00fczeylerine etkiyen s\u0131v\u0131 bas\u0131n\u00e7 kuvvetleri;<\/p>\n<p> F1=h\u00d7d\u00d7S1<br \/>\n F2=h2\u00d7d\u00d7S2=h\/2\u00d7d\u00d7S2<br \/>\n F3=h2\u00d7d\u00d7S3=h\/2\u00d7d\u00d7S3<\/p>\n<p> Pascal Prensibi<br \/>\n S\u0131v\u0131lar bas\u0131nc\u0131 aynen her do\u011frultuda iletirler. Sadece do\u011frultu ve y\u00f6n\u00fcn\u00fc de\u011fi\u015ftirirler. Bundan yararlanarak Su cenderesi, hidrolik fren&#8230; gibi sistemler yap\u0131labilir.<br \/>\n \u015eekildeki su cenderesinde Bas\u0131nc\u0131n etki y\u00fczeyi de\u011fi\u015ftirilerek istenilen b\u00fcy\u00fckl\u00fckte bas\u0131n\u00e7 elde edilebilir.<\/p>\n<p> kuvvetinin yapt\u0131\u011f\u0131 bas\u0131n\u00e7 her noktaya aynen iletilece\u011finden, P1=P2 den F1\/S1=F2\/S2 olur.<\/p>\n<p> Gazlarda Bas\u0131n\u00e7<br \/>\n A\u00e7\u0131k Hava bas\u0131nc\u0131 (P0): Atmosfer ad\u0131n\u0131 verdi\u011fimiz ve kal\u0131nl\u0131\u011f\u0131 kilometreleri bulan hava yerk\u00fcreyi ku\u015fatmaktad\u0131r. A\u00e7\u0131k hava hem yery\u00fcz\u00fcne hem de i\u00e7erisinde bulunan b\u00fct\u00fcn y\u00fczeylere a\u011f\u0131rl\u0131\u011f\u0131 nedeniyle bir kuvvet uygular. Bu kuvvetin y\u00fczeyin birim alan\u0131na d\u00fc\u015fen k\u0131sm\u0131na a\u00e7\u0131k hava bas\u0131nc\u0131 yada atmosfer bas\u0131nc\u0131 denir.<\/p>\n<p> Tori\u00e7elli deneyi<br \/>\n Tori\u00e7elli 80-90cm uzunlu\u011funda bir Cam boru alarak tamamen civa ile doldurmu\u015ftur. Daha sonra civa dolu cam boruyu ters \u00e7evirerek, i\u00e7erisinde civa bulunan civa kab\u0131na koyduktan sonra burudaki civan\u0131n bir k\u0131sm\u0131n\u0131n civa kab\u0131na bo\u015fald\u0131\u011f\u0131n\u0131 ve 76cm y\u00fcksekli\u011fini alacak \u015fekilde dengede kald\u0131\u011f\u0131n\u0131 g\u00f6zlemi\u015ftir. Civan\u0131n tamamen bo\u015falmamas\u0131n\u0131n sebebi, a\u00e7\u0131k hava Bas\u0131nc\u0131n\u0131n borudaki civa bas\u0131nc\u0131n\u0131 dengelemesidir. Yani borudaki civa(s\u0131v\u0131) bas\u0131nc\u0131 kaptaki civan\u0131n \u00fcst y\u00fczeyine etkiyen a\u00e7\u0131k hava Bas\u0131nc\u0131na e\u015fittir. <\/p>\n<p> Tori\u00e7elli bu deneyi de\u011fi\u015fik kesitteki borularla denemi\u015f ve sonucun de\u011fi\u015fmedi\u011fini g\u00f6zlemi\u015ftir. O halde civa y\u00fcksekli\u011fi borunun kesitine ba\u011fl\u0131 de\u011fildir. Tori\u00e7elli bu deneyi deniz k\u0131y\u0131s\u0131nda ve S\u0131cakl\u0131\u011f\u0131n 0\u00b0C oldu\u011fu bir G\u00fcnde yapm\u0131\u015ft\u0131r. <\/p>\n<p> Civan\u0131n \u00f6za\u011f\u0131rl\u0131\u011f\u0131 13.6 oldu\u011fundan borudaki s\u0131v\u0131 bas\u0131nc\u0131(ki bu bas\u0131n\u00e7 a\u00e7\u0131k hava bas\u0131nc\u0131na e\u015fittir);<\/p>\n<p> P0=h\u00d7d=1Atm olur.<br \/>\n A\u00e7\u0131k hava bas\u0131nc\u0131n\u0131 \u00f6l\u00e7en aletlere barometre denir. Barometredeki civa seviyesi her 10.5m y\u00fcksekli\u011fe \u00e7\u0131k\u0131ld\u0131k\u00e7a 1mm d\u00fc\u015fer. Bundan yararlanarak rak\u0131m \u00f6l\u00e7\u00fcl\u00fcr.<\/p>\n<p> Kapal\u0131 Kaplardaki Gazlar\u0131n Bas\u0131nc\u0131: S\u0131v\u0131lar gibi gazlarda i\u00e7inde bulunduklar\u0131 kab\u0131n \u00e7eperlerine bas\u0131n\u00e7 uygularlar. Bu bas\u0131n\u00e7 Gaz molek\u00fcllerinin hareketinden ileri gelir. Kapal\u0131 bir kapta bulunan gaz bas\u0131nc\u0131;<\/p>\n<p> 1.Hacimle ters orant\u0131l\u0131d\u0131r. S\u0131cakl\u0131k sabit kalmak \u015fart\u0131yla Hacim azald\u0131k\u00e7a bas\u0131n\u00e7 artar.<\/p>\n<p> 2.Hacim sabit kalmak \u015fart\u0131yla, s\u0131cakl\u0131k artt\u0131k\u00e7a bas\u0131n\u00e7 artar.<\/p>\n<p> 3.Molek\u00fcl say\u0131s\u0131 ile do\u011fru orant\u0131l\u0131d\u0131r. Hacim sabit iken Molek\u00fcl say\u0131s\u0131 artt\u0131k\u00e7a bas\u0131n\u00e7 artar.<br \/>\n Bu \u00fc\u00e7 Madde ideal gaz denklemi ile ifade edilir<\/p>\n<p> P.V=n.R.T<\/p>\n<p> P:bas\u0131n\u00e7 V: hacim<br \/>\n N:molek\u00fcl say\u0131s\u0131 R: genel gaz sabiti<br \/>\n T:s\u0131cakl\u0131k(T=273+t\u00b0C) <\/p>\n","protected":false},"excerpt":{"rendered":"<p>Kat\u0131 S\u0131v\u0131 ve Gazlar a\u011f\u0131rl\u0131klar\u0131 nedeniyle bulunduklar\u0131 y\u00fczeye bir kuvvet uygularlar. Kuvvetin kayna\u011f\u0131 ne olursa olsun birim y\u00fczeye dik olarak etki eden kuvvete bas\u0131n\u00e7(P), b\u00fct\u00fcn y\u00fczeye dik olarak etki eden kuvvete de Bas\u0131n\u00e7 kuvveti(F) denir. Bas\u0131n\u00e7 ile bas\u0131n\u00e7 kuvveti aras\u0131nda; P=F\/S ba\u011f\u0131nt\u0131s\u0131 vard\u0131r. Kat\u0131larda Bas\u0131n\u00e7 Kat\u0131 cisimler a\u011f\u0131rl\u0131klar\u0131 nedeniyle bulunduklar\u0131 y\u00fczeye bas\u0131n\u00e7 yaparlar. Taban alan\u0131 &hellip;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1407,1403],"tags":[2158,11682,11684,11683,6928],"class_list":["post-6321","post","type-post","status-publish","format-standard","hentry","category-fen-ve-teknoloji-odevleri","category-odevler","tag-basinc","tag-katilarda-basinc","tag-pascal-prensibi","tag-sivilarda-basinc","tag-toricelli-deneyi"],"_links":{"self":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/6321","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/comments?post=6321"}],"version-history":[{"count":0,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/6321\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/media?parent=6321"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/categories?post=6321"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/tags?post=6321"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}