Mol : Avagadro say\u0131s\u0131 ( 6,02.1023 ) kadar atom yada molek\u00fcl i\u00e7eren maddeye 1 mol denir.<\/p>\n
\u00d6rnek : 1 mol HF 6,02.1023 tane HF molek\u00fcl\u00fcd\u00fcr. Yine bu molek\u00fcl\u00fcn i\u00e7erisinde 1 mol H atomu (6,02.1023tane) ve 1 mol F atomu (6,02.1023 tane) vard\u0131r.<\/p>\n
Atom A\u011f\u0131rl\u0131\u011f\u0131 : 12C izotopu standart se\u00e7ilerek di\u011fer elementlerin bu izotopla k\u0131yaslanmas\u0131 sonucu hesaplanan k\u00fctlelerdir. \u00d6rne\u011fin, H=1 O=16 N=14 S=32<\/p>\n
1 Atomik K\u00fctle Birimi (a.k.b) : 1\/ 6,02.1023 = 1,66.10-24 gramd\u0131r.<\/p>\n
Molek\u00fcl A\u011f\u0131rl\u0131\u011f\u0131 : Bile\u015fi\u011fi olu\u015fturan elementlerin gram cinsinden k\u00fctlelerinin toplam\u0131na denir.<\/p>\n
\u00d6rnek : 1 mol C6H12O6 (glikoz) ka\u00e7 gramd\u0131r ? (C=12 O=16 H=1)<\/p>\n
6.12 = 72 gram C
\n12.1 = 12 gram H
\n6.16 = 96 gram O
\n——————————-
\n180 gram<\/p>\n
Bir Tane Molek\u00fcl\u00fcn K\u00fctlesi : Bir tek molek\u00fcl\u00fcn k\u00fctlesi molek\u00fcl a\u011f\u0131rl\u0131\u011f\u0131n\u0131n Avagadro say\u0131s\u0131na b\u00f6l\u00fcm\u00fcyle bulunur .
\n1 tek molek\u00fcl\u00fcn k\u00fctlesi = MA\/6,02.1023<\/p>\n
\u00d6rnek : 1 tane H2O molek\u00fcl\u00fc ka\u00e7 gramd\u0131r ? (H=1 O=16)<\/p>\n
1 tane H2O = 18\/ 6.1023 = 3.10-23 gramd\u0131r.
\nBir Tane Atomun K\u00fctlesi : Atom a\u011f\u0131rl\u0131\u011f\u0131n\u0131n Avagadro say\u0131s\u0131na oran\u0131d\u0131r.
\n1 tek atomun k\u00fctlesi = A.A.\/ 6,02.1023
\n\u00f6rnek : 1 tane C atomu ka\u00e7 gramd\u0131r ? (C=12)
\n1 tane C atomu = 12\/6.1023 = 2.10-23 gramd\u0131r.
\nN.\u015e.A\u2019 da Hacim : B\u00fct\u00fcn gazlar\u0131n bir mol\u00fc N.\u015e.A\u2019da ( 0 0C ve 1 atmosfer de) 22,4 litredir.<\/p>\n
Mol Hesaplama Y\u00f6ntemleri :
\nm Verilen Litre Verilen tanecik Say\u0131s\u0131
\nn= n= n=
\nMA 22,4 6,02.1023
\n\u00d6rnek : 23 gram C2H5OH ka\u00e7 mold\u00fcr ? (C=12 O=16 H =1)
\nMA = 2.12 + 6.1 + 16.1= 46 gram\/mol
\nn=23\/46 = 0,5 mol
\n\u00d6rnek : N.\u015e.A\u2019da 2,8 litre olan CO2 gaz\u0131 ka\u00e7 mol ve ka\u00e7 gramd\u0131r ?(C=12 O=16)
\nn=2,8\/22,4 = 0,125 mol.
\n1 mol CO2 44 gram oldu\u011funa g\u00f6re 0,125 mol CO2 0,125.44= 5,5 gramd\u0131r.
\n22,4 litre = 1 mol : 11,2 litre= 0,5 mol : 5,6 litre = 0,25 mol : 2,8 Litre = 0,125 mol<\/p>\n
\u00d6rnek : 3,01.1023 tane C2H4 molek\u00fcl\u00fc ka\u00e7 gramd\u0131r ? (C=12 H=1)
\nn=3,01.1023\/6,02.1023= 0,5 mol 1 mol C2H4 28 gram ise 0,5 mol C2H4 14 gram olur.<\/p>\n
K\u00fctlece y\u00fczde = (Elementin bile\u015fikteki k\u00fctlesi\/toplam k\u00fctle)x100
\nI. elementin bile\u015fikteki k\u00fctlesi I. elementin verilen gram\u0131
\n=
\nII. elementin bile\u015fikteki k\u00fctlesi II. elementin verilen gram\u0131<\/p>\n
I. elementin bile\u015fikteki k\u00fctlesi I. elementin verilen y\u00fczdesi
\n=
\nII. elementin bile\u015fikteki k\u00fctlesi II. elementin verilen y\u00fczdesi<\/p>\n
\u00c7\u00d6Z\u00dcML\u00dc TEST<\/p>\n
1
\n. I- 16 gram oksijen gaz\u0131
\nII- 3,01.1023 tane He gaz\u0131
\nIII- 6 gam C i\u00e7eren CO2 gaz\u0131<\/p>\n
yukar\u0131daki gazlar\u0131n N.\u015e.A.\u2019 da kaplad\u0131klar\u0131 hacim hangi se\u00e7enekte do\u011fru olarak
\nverilmi\u015ftir ?(C=12 O=16)<\/p>\n
A) I>II>III B) I=II>III
\nC) I=II=III D) II>III>I
\nE) I=III>II<\/p>\n
\u00c7\u00f6z\u00fcm : I- n=16\/32 = 0,5 mol
\n0,5. 22,4 = 11,2 litre
\nII- 3,01.102376,02.1023=0,5 mol 0,5.22,4 = 11,2 litre
\nIII- 6 gram C i\u00e7eren CO2 0,5 mold\u00fcr. 0,5.22,4 = 11,2 litre<\/p>\n
Cevap C<\/p>\n
2. 3,01.1022 tane X(OH)2 3,7 gram oldu\u011funa g\u00f6re X in atom a\u011f\u0131rl\u0131\u011f\u0131 ka\u00e7t\u0131r ? (O=16 H=1)<\/p>\n
A) 74 B) 32 C) 40
\nD) 56 E) 14<\/p>\n
\u00c7\u00f6z\u00fcm : n= 3,01.1023\/ 6,02.1023 = 0,05 mol<\/p>\n
0,05 mol 3,7 gramsa<\/p>\n
1 mol X<\/p>\n
X= 74 gram\/ mol<\/p>\n
X=40 gr\/mol\uf0deX+32+2= 74
\nCevap C<\/p>\n
3. 8 gram oksijen gaz\u0131nda ka\u00e7 tane atom
\nvard\u0131r ? (O=16)<\/p>\n
A) 3,01.1023 B) 6,02.1023
\nC) 12,04.1023 D) 1,505.1023
\nD) 24,08.1023<\/p>\n
\u00c7\u00f6z\u00fcm : n= 8\/32= 0,25 mol O2 gaz\u0131<\/p>\n
1 mol O2 molek\u00fcl\u00fcnde 2.6,02.1023 tane atom varsa<\/p>\n
0,25 mol O2 de X<\/p>\n
X= 3,01.1023 tane atom Cevap A<\/p>\n
4. 0,2 mol X2Y3 32 gram gelmektedir. Y nin atom a\u011f\u0131rl\u0131\u011f\u0131 16 oldu\u011funa g\u00f6re X in atom a\u011f\u0131rl\u0131\u011f\u0131n\u0131n Y nin atom a\u011f\u0131rl\u0131\u011f\u0131na oran\u0131 nedir ?<\/p>\n
A) 2\/3 B) 3\/2 C) 1
\nD) 3\/7 E) 7\/2<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
0,2 mol 32 gramsa<\/p>\n
1 mol ?<\/p>\n
?= 160 gr\/mol<\/p>\n
X= 56 gr\/mol\uf0de2.X + 3.16 = 160 <\/p>\n
X\/Y= 7\/2\uf0deX\/Y = 56\/16 Cevap E<\/p>\n
5.<\/p>\n
I- XY bile\u015fi\u011finin molek\u00fcl a\u011f\u0131rl\u0131\u011f\u0131 28 dir.
\nII- XY2 bile\u015fi\u011finin molek\u00fcl a\u011f\u0131rl\u0131\u011f\u0131 44 d\u00fcr.<\/p>\n
Buna g\u00f6re X ve Y nin atom a\u011f\u0131rl\u0131klar\u0131 s\u0131ras\u0131yla nedir ?<\/p>\n
A) 24-32 B) 14-12 C) 12-16
\nD) 32-23 E) 12-14
\n\u00c7\u00f6z\u00fcm :<\/p>\n
2 X + Y = 28
\nX + 2Y = 44<\/p>\n
X= 12 Y= 16 Cevap C<\/p>\n
6. K\u00fctlece %80 X i\u00e7eren X2H6 bile\u015fi\u011finde X in atom a\u011f\u0131rl\u0131\u011f\u0131 ka\u00e7t\u0131r ?<\/p>\n
A) 12 B) 14 C) 23
\nD) 27 E) 40<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
2.X \/ 6.1 = X= 12 Cevap A\uf0de80\/20 <\/p>\n
7. NH3 + CO kar\u0131\u015f\u0131m\u0131 N.\u015e.A da 11,2 litre olup kar\u0131\u015f\u0131m\u0131n k\u00fctlesi 11,8 gram gelmektedir. Kar\u0131\u015f\u0131mdaki CO nun mol % si nedir ?
\n( C=12 O=16 N=14 H=1)<\/p>\n
A) 20 B) 40 C) 60
\nD) 80 E) 90<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
NH3 + CO = 0,5 mol; NH3 x mol ise CO = 0,5-x mold\u00fcr.<\/p>\n
0,5. 17 + (0,5-x).28 = 11,8 gram
\nX=0,2 mol NH3 CO = 0,3 mol olur.<\/p>\n
0,5 molde 0,3 mol CO varsa<\/p>\n
100 molde X<\/p>\n
X= 60 Cevap C<\/p>\n
8. 1,806.1023 tane atom i\u00e7eren SO3 gaz\u0131 N.\u015e.A da ka\u00e7 litre hacim kaplar ?<\/p>\n
A) 6,72 B) 22,4 C) 2,24
\nD) 1,68 E ) 4,48<\/p>\n
\u00c7\u00f6z\u00fcm : n= 1,806.1023\/6,02.1023 = 0,3 mol atom<\/p>\n
1 mol SO3 de toplam 4 mol atom varsa<\/p>\n
X mol 0,3 mol atom<\/p>\n
X= 0,075 mol V= 0,075.22,4 = 1,68 litre<\/p>\n
Cevap D<\/p>\n
9. 3,01.1023 tane CO molek\u00fcl\u00fc, N.\u015e.A da 5,6 litre hacim kaplayan N2 gaz\u0131 ve 7,5 gram NO gaz\u0131ndan olu\u015fan kar\u0131\u015f\u0131m\u0131n k\u00fctlesi ka\u00e7 gramd\u0131r ?<\/p>\n
A) 14 B) 21 C) 22
\nD) 28,5 E) 32,5<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
CO= 3,01.1023\/6,02.1023 = 0,5 mol .28 = 14 gr<\/p>\n
N2 = 5,6\/22,4 = 0,25 mol . 28=7 gr
\n= 7,5 gr<\/p>\n
NO= 7,5 gr<\/p>\n
Mt= 14+7+7,5 = 28,5 gr. Cevap D<\/p>\n
10. E\u015fit molek\u00fcl say\u0131da bir kar\u0131\u015f\u0131m elde edebilmek i\u00e7in 15 gram C2H6 gaz\u0131na N.\u015e.A da ka\u00e7 litre C3H4 eklenmelidir ? (C=12 H=1)<\/p>\n
A) 5,6 B) 2,24 C) 22,4
\nD) 1,12 E) 11,2<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
C2H6= 15\/30 = 0,5 mol<\/p>\n
Molek\u00fcl say\u0131lar\u0131n\u0131n e\u015fit olmas\u0131 demek mol say\u0131lar\u0131n\u0131n e\u015fit olmas\u0131 demektir. O halde C2H6 da 0,5 mol olmal\u0131d\u0131r.<\/p>\n
0,5.22,4 = 11,2 litre C3H4 Cevap E<\/p>\n
11. X2H4 bile\u015fi\u011fi ile XO bile\u015fi\u011fi e\u015fit k\u00fctlede ve molek\u00fcl say\u0131lar\u0131 da e\u015fit oldu\u011funa g\u00f6re X in atom a\u011f\u0131rl\u0131\u011f\u0131 nedir ?(O=16 H=1)<\/p>\n
A) 12 B) 14 C) 16
\nD) 32 E) 40<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
Molek\u00fcl say\u0131lar\u0131 e\u015fitse mol say\u0131lar\u0131 da e\u015fittir. K\u00fctlelerde e\u015fit oldu\u011funa g\u00f6re molek\u00fcl a\u011f\u0131rl\u0131klar\u0131 da e\u015fittir.<\/p>\n
X= 12\uf0de2.X + 4.1 = X+16 Cevap A<\/p>\n
12. XY3 bile\u015fi\u011finin molek\u00fcl a\u011f\u0131rl\u0131\u011f\u0131 MgY bile\u015fi\u011finin molek\u00fcl a\u011f\u0131rl\u0131\u011f\u0131n\u0131n 2 kat\u0131 oldu\u011funa g\u00f6re Y elementinin atom a\u011f\u0131rl\u0131\u011f\u0131 ka\u00e7t\u0131r? (X=32, Mg=24)<\/p>\n
A) 12 B) 16 C) 23
\nD) 24 E) 40<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
(32 + 3.Y) Y = 16 Cevap B\uf0de= 2.(24 + Y) <\/p>\n
13. 0,01 mol\u00fcnde 0,02 mol X ve 0,03 mol Y bulunan bile\u015fi\u011fin form\u00fcl\u00fc a\u015fa\u011f\u0131dakilerden hangisidir ?<\/p>\n
A) XY B) XY2 C) X2Y3
\nD) XY3 E) X2Y<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
1 molde 2 mol X ve 3 mol Y bulunaca\u011f\u0131ndan bile\u015fik X2Y3 olur.
\nCevap C<\/p>\n
14. 0,5 mol CuSO4XH2O bile\u015fi\u011fi 125 gram ise X say\u0131s\u0131 nedir ? (Cu=64 S=32 H=1 O=16)<\/p>\n
A) 2 B) 3 C) 4
\nD) 5 E) 6<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
0,5 mol CuSO4XH2O 125 gram ise<\/p>\n
1 mol ?<\/p>\n
? = 250 gram<\/p>\n
64 + 32 +64 + 18.X =\uf0deCuSO4XH2O = 250 250<\/p>\n
X= 5 Cevap D<\/p>\n
15.0,2 mol\u00fcnde 2,4 gram X ve 3,2 gram Y bulunduran bile\u015fi\u011fin bir molek\u00fcl\u00fcn\u00fcn k\u00fctlesi ka\u00e7 gramd\u0131r ?<\/p>\n
A) 28 B) 28\/6,02.1023<\/p>\n
C) 14\/6,02.1023 D) 6,02.1023<\/p>\n
E) 6,02.1023\/28<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
1 mol bile\u015fikte 12 gram X ve 16 gram Y bulunaca\u011f\u0131ndan bile\u015fi\u011fin molek\u00fcl a\u011f\u0131rl\u0131\u011f\u0131 28 gram d\u0131r. 1 molek\u00fcl\u00fcn k\u00fctlesi MA\/ 6,02.10 23 oldu\u011fundan 28\/6,02.1023 olur.
\nCevap B<\/p>\n
16. 2 mol CO2 i\u00e7in ;<\/p>\n
I- 2 mol C i\u00e7erir.
\nII- 4 mol O atomu i\u00e7erir.
\nIII- 6,02.1023 tane CO2 molek\u00fcl\u00fcd\u00fcr.
\nIV- Toplam atom say\u0131s\u0131 6×6,02.1023 d\u00fcr.<\/p>\n
Yarg\u0131lar\u0131ndan hangisi yada hangileri do\u011frudur ?<\/p>\n
A) I ve II B) I ve III C) II ve III
\nD) I,II ve IV E) II,III ve IV<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
I- 1 mol CO2 de 1 mol C varsa 2 mol CO2 de 2 mol C olur.
\nII- 1 mol CO2 de 2 mol O varsa 2 molde 4 mol O olur.
\nIII- 1 mol CO2 6,02.1023 tane CO2 dir. 2 mol ise 1,204.1023 tane CO2 molek\u00fcl\u00fcd\u00fcr.
\nIV- 1 mol de 3×6,02.1023 tane atom varsa 2 mol de 6×6,02.1023 tane atom bulunur.<\/p>\n
Cevap D<\/p>\n
17. CuSO45H2O bile\u015fi\u011finin k\u00fctlece % ka\u00e7\u0131 H2O dur ? (CUSO4=160 H2O=18)<\/p>\n
A) 18 B) 36 C) 54
\nD) 72 E) 90<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
1 mol CuSO45H2O= 250 gram olup 90 gram\u0131 sudur.<\/p>\n
250 gram da 90 gram su varsa<\/p>\n
100 gramda X<\/p>\n
X= 36 Cevap B<\/p>\n
18. 8 gram XH4 12,04.1023 tane H atomu i\u00e7erdi\u011fine g\u00f6re 1 mol XH4 ka\u00e7 gramd\u0131r ?<\/p>\n
A) 8 B) 16 C) 32
\nD) 64 E) 80<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
n= n= 2 mol H atomu\uf0de12,04.1023\/6,02.1023 <\/p>\n
2 mol H atomu i\u00e7eren bile\u015fik 8 gram ise<\/p>\n
4 mol H i\u00e7eren bile\u015fik ?<\/p>\n
? = 16 gram Cevap B<\/p>\n
19.X2S in 0,1 mol \u00fc 3,4 gram\u0131 ise X2O nun
\n0,2 mol \u00fc ka\u00e7 gramd\u0131r ?(S=32 O=16)<\/p>\n
A) 1 B) 18 C) 3,6
\nD) 2,8 E) 3,2<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
0,1 mol X2S 3,4 gram ise 1 mol\u00fc 34 gram olup X in atom a\u011f\u0131rl\u0131\u011f\u0131 1 olur. X2O= 18 olup 0,2 mol\u00fc 3,6 gram olur.
\nCevap C
\n20. A\u015fa\u011f\u0131dakilerden hangisi N.\u015e.A da en fazla hacim kaplar ? (C=12 H=1 He=4 N=14)<\/p>\n
A) NH3 B) He C) CO D) NO E) N2O<\/p>\n
\u00c7\u00f6z\u00fcm: Molek\u00fcl a\u011f\u0131rl\u0131\u011f\u0131 k\u00fc\u00e7\u00fck olan\u0131n mol\u00fc b\u00fcy\u00fck olur. Mol say\u0131s\u0131 b\u00fcy\u00fck olan\u0131n hacmi de b\u00fcy\u00fckt\u00fcr.
\nCevap B<\/p>\n
21.
\nI- 6,02.1022 tane SO2 molek\u00fcl\u00fc
\nII- N.\u015e.A da 8,96 Lt hacim kaplayan NH3 gaz\u0131
\nIII- 0,1 mol SO3 gaz\u0131<\/p>\n
Yukar\u0131da verilen gazlar\u0131n k\u00fctleleri aras\u0131ndaki ili\u015fki a\u015fa\u011f\u0131dakilerden hangisidir ?
\n(S=32 O=16 N=14 H=1)<\/p>\n
A) I>II>III B) III>II>I C) II>III>I
\nD) I=II>III E) III=II>I<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
SO2 = 6,02.1022\/6,02.1023 = 0,1 mol
\n0,1 .64 = 6,4 gram SO2<\/p>\n
NH3= 8,96\/22,4 = 0,4 mol
\n0,4.17 = 6,8 gramNH3<\/p>\n
0,1.80= 8 gram SO3<\/p>\n
Buna g\u00f6re III>II>I dir. Cevap B<\/p>\n
22.C3H6 gaz\u0131 i\u00e7in a\u015fa\u011f\u0131dakilerden
\nhangisi yanl\u0131\u015ft\u0131r ?(C=12 H=1)<\/p>\n
A) N.\u015e.A da 4,48 litresi 8,4 gramd\u0131r.
\nB) N.\u015e.A da \u00f6z k\u00fctlesi 1,875 gr \/ lt dir.
\nC) 1,204.1023 tanesi N.\u015e.A da 4,48 lt dir.
\nD) 0,5 mol\u00fc 4,5 tane atom i\u00e7erir.
\nE) 3,01.1022 tane molek\u00fcl\u00fc 1,8 gr C i\u00e7erir.<\/p>\n
\u00c7\u00f6z\u00fcm : 1mol C3H6 da 9 mol atom varken 0,5 mol C3H6 4,5 tane de\u011fil 4,5 mol atom bulunur.<\/p>\n
Cevap D<\/p>\n
23. Avagadro say\u0131s\u0131 kadar atom i\u00e7eren Fe2O3(k) bile\u015fi\u011fi i\u00e7in a\u015fa\u011f\u0131dakilerden
\nhangisi do\u011frudur ?(Fe=56 O=16)<\/p>\n
A) 32 gramd\u0131r.
\nB) 5 mol d\u00fcr.
\nC) N.\u015e.A. da 22,4 litredir.
\nD) 2 mol Fe i\u00e7erir.
\nE) 48 gram O i\u00e7erir.<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
Avagadro say\u0131s\u0131 kadar atom= 1 mol atom
\n1 mol Fe2O3 de 5 mol atom varsa<\/p>\n
X mol 1 mol atom
\nX= 0,2 mol Fe2O3 d\u00fcr.
\n1 mol Fe2O3 160 gram oldu\u011funa g\u00f6re 0,2 mol \u00fc 32 gramd\u0131r.
\nCevap A
\n24. 0,4 mol SO2 ile N.\u015e.A da 11,2 litre hacim kaplayan CO gaz\u0131nda toplam ka\u00e7 mol O atomu vard\u0131r ?<\/p>\n
A) 0,8 B) 0,5 C) 2,5
\nC) 1,3 D) 0,9<\/p>\n
\u00c7\u00f6z\u00fcm : 1 mol SO2 de 2 mol O varsa<\/p>\n
0,4 mol de X<\/p>\n
X= 0,8 mol O atomu<\/p>\n
1 mol CO da 1 mol O varsa<\/p>\n
0,5 mol O da X<\/p>\n
X= 0,5 mol O atomu<\/p>\n
0,5 + 0,8 = 1,3 mol O atomu<\/p>\n
Cevap C<\/p>\n
25. 11,2 gram C2H4 gaz\u0131 i\u00e7in a\u015fa\u011f\u0131dakilerden hangisi yanl\u0131\u015ft\u0131r ?(C=12 H=1)<\/p>\n
A) 4,8 gram C i\u00e7erir.
\nB) 1,6 gram H i\u00e7erir.
\nC) 0,5 mol d\u00fcr.
\nD) 2,408.1023 tane molek\u00fcl i\u00e7erir.
\nE) N.\u015e.A da 8,96 litre hacim kaplar.<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
n=0,4 mol. Cevap\uf0den= 11,2\/28 C<\/p>\n
26. 0,4 mol\u00fc 40 gram olan bile\u015fik a\u015fa\u011f\u0131dakilerden hangisidir ? ( C=12 S=32 Ca=40 O=16 N=14)<\/p>\n
A) NH3 B) Ca(OH)2 C) NO
\nD) CaCO3 E) SO3<\/p>\n
\u00c7\u00f6z\u00fcm :<\/p>\n
0,4 mol 40 gramsa<\/p>\n
1 mol X<\/p>\n
X= 100 gram CaCO3=100 oldu\u011fundan<\/p>\n
Cevap D<\/p>\n","protected":false},"excerpt":{"rendered":"
Mol : Avagadro say\u0131s\u0131 ( 6,02.1023 ) kadar atom yada molek\u00fcl i\u00e7eren maddeye 1 mol denir. \u00d6rnek : 1 mol HF 6,02.1023 tane HF molek\u00fcl\u00fcd\u00fcr. Yine bu molek\u00fcl\u00fcn i\u00e7erisinde 1 mol H atomu (6,02.1023tane) ve 1 mol F atomu (6,02.1023 tane) vard\u0131r. Atom A\u011f\u0131rl\u0131\u011f\u0131 : 12C izotopu standart se\u00e7ilerek di\u011fer elementlerin bu izotopla k\u0131yaslanmas\u0131 sonucu …<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1407,1403],"tags":[2195,2194,2196],"class_list":["post-750","post","type-post","status-publish","format-standard","hentry","category-fen-ve-teknoloji-odevleri","category-odevler","tag-avagadro-sayisi","tag-mol-kavrami","tag-molekul"],"_links":{"self":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/750","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/comments?post=750"}],"version-history":[{"count":0,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/posts\/750\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/media?parent=750"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/categories?post=750"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.islamidavet.com\/kutuphane\/wp-json\/wp\/v2\/tags?post=750"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}